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Yuki888 [10]
3 years ago
10

Describe the main differences beA human cell has 46 chromosomes. At the end of mitosis, there are two cells, each with 46 chromo

somes, for a total of 92 chromosomes split between both cells.
Which statement describes meiosis in a human cell?

At the end of meiosis, there are two cells, each with 46 chromosomes, for a total of 92 chromosomes split between both cells.
At the end of meiosis, there are four cells, each with 23 chromosomes, for a total of 92 chromosomes split between the four cells.
At the end of meiosis, there are four cells, each with 46 chromosomes, for a total of 184 chromosomes split between the four cells.
At the end of meiosis, there are two cells, each with 23 chromosomes, for a total of 184 chromosomes split between both cells. tween meiosis and mitosis.
Chemistry
1 answer:
liberstina [14]3 years ago
6 0

Answer:

At the end of meiosis, there are four cells, each with 23 chromosomes, for a total of 92 chromosomes split between the four cells.

Explanation:

During meiosis, a diploid cell  (46 chromosomes) replicates its DNA (making 92 chromosomes) then undergoes two cell divisions to generate four haploid cells (23 chromosomes).

These haploid cells are the gametes which, during fertilization, fuse to become a zygote with 46 chromosomes.

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Why is it good practice to perform a mixed melting point determination at two different ratios of unknown to known materials in
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References Use the References to access important values if needed for this question A student ran the following reaction in the
ANTONII [103]

Answer:

19.27

Explanation:

Some values are corrected from correct source.Thus,

Moles of SO₂ = 8.19x10⁻² moles

Moles of O₂ = 8.10x10⁻² moles

Volume = 1 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Concentration of SO₂ = 8.19x10² M

Concentration of O₂ = 8.10x10 M

Considering the ICE table for the equilibrium as:

                    2SO₂ (g) +    O₂ (g)     ⇔          2SO₃ (g)

t = o              8.19x10⁻²      8.19x10⁻²

t = eq                -2x                  -x                      2x

--------------------------------------------- --------------------------

neq:    8.19x10⁻² -2x       8.19x10⁻² -x                      2x

Given:  

Equilibrium concentration of  O₂ = 5.98x10⁻² M  = 8.19x10⁻² -x

Thus, x = 0.0212 M

[SO₂] = 8.19x10⁻² - 2*0.0212 = 0.0395 M

[SO₃] = 2*0.0212 = 0.0424 M

The expression for the equilibrium constant is:

K_c=\frac {[SO_3]^2}{[SO_2]^2[O_2]}  

K_c=\frac{{0.0424}^2}{{0.0395}^2\times 0.0598}  

K = 19.27

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How to balance N2 H2 NH3
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N2 H2 ——> NH3

Add a 3 in front of H2 and a 2 in front of NH3

So the answer would be

N2 3H2 ——> 2NH3
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