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vodomira [7]
3 years ago
5

Which equation represents the graph of the linear function?

Mathematics
1 answer:
blsea [12.9K]3 years ago
6 0
I think the answer is D

Hope it helps
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A toy manufacturer claims that the mean time that its top-selling toy captures children's attention is at least 45 minutes. Supp
riadik2000 [5.3K]

Answer:

H_0:\mu =45\\\\H_a:\mu\geq 45

Step-by-step explanation:

Since we have given that

A toy manufacturer claims that the mean time that its top-selling toy captures children's attention is at least 45 minutes.

Since we need to carry out a hypothesis test whether he can refute the claim.

We always take the alternate hypothesis such that it should satisfy the given statement.

And the null hypothesis can be equal to mean or other than that is given in alternate hypothesis.

So, hypothesis :

H_0:\mu =45\\\\H_a:\mu\geq 45

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3 years ago
Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!
valkas [14]

Answer by JKismyhusbandbae: expression 2 and expression 1

Look at the four expressions. Simplify any expressions that can be simplified to see which two are equivalent.

8v × 30v = ( 8 × 30) × ( v × v) = 240v^2

Since expression 2 can be simplified to expression 1, they are equivalent.

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Wirte an expression that should have a variable and a constant
e-lub [12.9K]
7x+5
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3 years ago
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What does x equal in this question
miskamm [114]
Theirs a trick to cheat on khan academy

1) Turn off Wifi
2) Go to hint and get the answer
3) Take picture of answer or remember it
4) Go to inspect element ——> arrows that look like this “>>”—> Application—-> Local Storage (click it until it says khan academy .com etc then click that then go to “X” by value and next to it click that then turn on wifi and put the answer
5 0
3 years ago
Please someone help i dont know this :(
steposvetlana [31]

Answer:

D) None of the above

Step-by-step explanation:

These are no supplementary or complimentary because they do not add up to 180 and to be vertical they would have to be across from each other

5 0
3 years ago
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