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Goshia [24]
3 years ago
7

If Shelly wants to earn the most interest on her account, but knows she can only keep $100 in her account, which bank's checking

account would be best for her to use?
Mathematics
1 answer:
rjkz [21]3 years ago
3 0

Answer:

Chases bank account?

Step-by-step explanation:

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Quadrilateral ABCD is given, the interior angle at vertex B is 97 degrees and the exterior angle at vertex A is 88 degrees. Line
Citrus2011 [14]

Answer:

angle 1 = 83°

angle 2 = 88°

Step-by-step explanation:

angle 1 and angle on vertex B are

pair of co interior angles ( whose sum = 180° )

so, angle 1 + angle B = 180°

angle 1 = 180° - angle B

angle 1 = 180° - 97° = 83°

hence, angle 1 = 83°

but, angle 2 and exterior of vertex A forms alternate interior angle pair ,

so , angle 2 = angle A = 88°

i hope you got it ....

5 0
3 years ago
Write the equation of the line in point slope form that passes through the given point (4,-1);m=-6
Rashid [163]
The equation will be -6(x-4)-1
4 0
2 years ago
Read 2 more answers
Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north. At wha
Fiesta28 [93]

I've attached an image showing the coordinates of Ship A and Ship B.

Answer:

distressed vessel is located at (1, 1.5)

Step-by-step explanation:

From the image attached, we can see that;

Coordinate of ship A is (3, 4)

Coordinate of ship B is (1, 1)

Now, we are told that Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north.

This means that the distressed ship is somewhere in between ship A & B.

To solve this, we will extend the arrow line from Ship A in that same SW direction and we will do the same for ship B in the same North direction. Their point of intersection is where the distressed ship is located.

Now, if we do that, we will see that they will intersect at the point; (1, 1.5)

Thus,distressed vessel is located at (1, 1.5)

5 0
3 years ago
[(1/(3+x))-(1/3)] / x<br> Limit 0
Effectus [21]
First find a common denominator and combine the fractions in the numerator:

\displaystyle\lim_{x\to0}\frac{\dfrac1{3+x}-\dfrac13}x=\lim_{x\to0}\frac{\dfrac3{3(3+x)}-\dfrac{3+x}{3(3+x)}}x=\lim_{x\to0}\frac{3-(3+x)}{3x(3+x)}

Now simplify and cancel out all the terms that you can:

\displaystyle\lim_{x\to0}\frac{3-3-x}{3x(3+x)}=-\frac13\lim_{x\to0}\frac1{3+x}

Since the remaining expression is continuous as a function of x, you can directly substitute to end up with

\displaystyle-\frac13\lim_{x\to0}\frac1{3+x}=-\frac13\times\frac1{3+0}=-\frac19
8 0
2 years ago
A Special order for 1200 flowers is for roses and tulips
DaniilM [7]

Answer:

The ratio of roses to tulips is 2/5 in simplest form

7 0
3 years ago
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