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galben [10]
3 years ago
14

What is 6x^2-x-2 when factoring

Mathematics
1 answer:
lidiya [134]3 years ago
7 0
6x^2-x-2   this is of the form ax^2+bx+c

jk=ac=-12 and j+k=b=-1 so j and k must be -4 and 3 so

6x^2+3x-4x-2

3x(2x+1)-2(2x+1)

(3x-2)(2x+1)
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Answer:

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Step-by-step explanation:

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3 years ago
The height of a cone is twice the radius of its base.
fredd [130]

Answer: 2/3πx³

Step-by-step explanation:

Let the radius of the cone be represented by x.

Since the height of the cone is twice the radius of its base, the height will be: = 2x

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where,

r = x

h = 2x

Volume of a cone = 1/3πr²h

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3 0
3 years ago
What is the arc measure of BDC in degrees?<br> (4k + 159)<br> P<br> (2k + 153)
andre [41]
<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

(4k + 159)^{\circ}

And another arc, let's call it FGH. measures:

(2k + 153)^{\circ}

If those arc are equal, then this equation is true:

(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3

Substituting k into the first equation:

\angle BDC=(4(-3)+159)^{\circ} \\ \\ \angle BDC=(-12+159)^{\circ} \\ \\ \boxed{\angle BDC=147^{\circ}}

3 0
3 years ago
Read 2 more answers
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