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In-s [12.5K]
2 years ago
14

Please help!

Mathematics
2 answers:
zmey [24]2 years ago
8 0
7 x 10^-9
4 x 10^-7
1 x 10^4
2 x 10^4
Letter C
docker41 [41]2 years ago
6 0
So, the smaller the exponent the smaller the number. So one that is -9 is very small.
We first want to compare the numbers through the exponents.

-9 is the lowest exponent, meaning it is the smallest number, so any answer that doesn't start with 7×10^-9 is incorrect

Meaning we can cross out answer choices A and B

-7 is the next to smallest exponent, but Choices C and D both have 4×10^-7 as the second, so we cannot out anymore answers.

After that the final two numbers each have the same exponent, so then we look at the actual numbers.

Which are 1 and 2, they are each risen to the 4th power, meaning they have 4 zero's after the number.
So the two numbers we have are 10000 and 20000

10000 is less than 20000, so that means 1×10^4 comes next in our ordering of least to greatest, leaving 2×10^4 as the greatest

So we order them properly from least to greatest, and our chart is:

7×10^-9 < 4×10^-7 < 1×10^4 < 2×10^4

This is the same as answer choice C, so C is your answer! Hopefully this all makes sense!
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Jessica spent S28 on fruit at the grocery store. She spent a total of $40 at the store. What percentage of the total did she spe
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Clue #1: The sum of the digits of a 3 digit number is 20. Clue #2: The tens digit is 2 less than the hundreds digit. Clue #3: Th
o-na [289]

Answer: The number is 974

Step-by-step explanation:

First, any 3 digit number can be written as:

N = a*100 + b*10 + c

Where a, b, and c are single-digit numbers.

a is the hundreds digit

b is the tens digit

c is the unit digit

We can write the clues as:

#1: a + b + c = 20

#2: b = a - 2

#3: c = a + b - 12

Then we have a system of equations:

a + b + c = 20

b = a - 2

c = a + b - 12

To solve this, we need to isolate one of the variables in one equation and then replace this in the other equations, we can see that b is already isolated in the second equation, then we can replace that in the first and third equations:

a + (a - 2) + c = 20

c = a + (a - 2) - 12

Now we can see that c is isolated in the second equation, then we can replace that in the first one to get:

a + (a - 2) + (a + (a - 2) - 12) = 20

Now we can solve this for a:

a + a - 2 + a + a -2 - 12 = 20

4*a - 16 = 20

4*a = 20 + 16

4*a = 36

a = 36/4 = 9

With this, we can find the values of b and c.

b = a - 2 = 9 - 2 = 7

c = a + b - 12 = 9 + 7 - 12 = 4

Then the 3-digit number is:

N = a*100 + b*10 + c = 9*100 + 7*10 + 4 = 974

N = 974

6 0
3 years ago
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