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3 years ago

Bhavik bought 3 liters of milk and 5 loaves of bread for a total of $11. A month later, he bought 4 liters of milk

Mathematics

2 answers:

Ber [7]3 years ago

7 0

Answer:

Step-by-step explanation:

A liter of milk cost $.75

A loaf of bread cost $1.75

Alla [95]3 years ago

7 0

Answer:

Step-by-step explanation:

Cost of milk = $ m

Cost of bread = $ b

3m + 5b = 11 ------------------(I)

4m + 4b = 10 ----------------(II)

Multiply equation (I) by 4 and multiply equation (II) by (-3). Thus when you add, m will be eliminated and we can find the value of b

(I)*4 12m + 20b = 44

(II)*(-3) <u>-12m - 12b = -30</u> {Now add & m will be eliminated}

8b = 14

b = 14/8

b = $ 1.75

Cost of a loaf of bread = $ 1.75

Plugin the value of b in equation (I)

3m + 5*1.75 = 11

3m + 8.75 = 11

3m = 11 - 8.75

3m = 2.25

m = 2.25/3

m = $ 0.75

Cost of one liter of milk = $ 0.75

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

A new gas- and electric-powered hybrid car has recently hit the market. The distance traveled on 1 gallon of fuel is normally di

Doss [256]

Answer:

a) P [ Z > 70 ] = 0.1075 or 10.75 %

b) P [ Z < 60 ] = 0.1038 or 10.38 %

c) P [ 55 ≤ Z ≤ 70 ] = 0.8882 or 88.82 %

Step-by-step explanation:

Normal Distribution μ = 65 and σ = 4

a) The probability of the car travels more than 70 miles per gallon is:

P [ Z > 70 ] = (Z-μ) ÷ σ ⇒ P [ Z > 70 ] = (70-65) ÷4 P [ Z > 70 ] = 1.25

the point 1.25 corresponds at values, from left tail up to 70 so we must go and look for the area for the point 1.24 which is 0.8925. Then we have the area or probability of all cars traveling up to 70 miles therefore we have to subtract 1 -0,8925

P [ Z > 70 ] = 0.1075 or 10.75 %

b)The probability of the car travels less than 60 miles per gallon is:

P [ Z < 60 ] = ( 60 - μ ) ÷ σ ⇒ P [ Z < 60 ] = (60-65)÷ 4 P [ Z < 60 ] = -1.25

Again -1.25 corresponds to 60 miles per gallon threfore we move to the left and find for point -1.26 which area is 0.1038 so

P [ Z < 60 ] = 0.1038 10.38 %

c) P [ 55 ≤ Z ≤ 70]

For point Z = 70 or 1.25 (case a above) P [ Z ≤ 70] = (70-65)÷4

P [ Z ≤ 70] = 1.25

In this case we got the whole area from the left tail up to 1.25

P [ Z ≤ 70] = 0.8944 (includes the area of the point from the left tail up to the point assocciated to 55 miles and for that reason we have to subtract that area)

P [ Z ≥ 55 ] = (55-65) ÷ 4 P [ Z ≥ 55 ] = -2.5 and the area is 0.0062

So P [ 55 ≤ Z ≤ 70 ] = 0.8944 - 0.0062 = 0.8882

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dangina [55]

Answer:

Step-by-step explanation:

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Find the area of a circle circumscribing an equilateral triangle of side 15cm.<br> Take pi = 3.14.

miskamm [114]

Answer:

236 cm²

Step-by-step explanation:

Height of an equilateral triangle (h) = √3 /2 (l)

l = side of the equilateral triangle.

h = √3 /2 (15)

In an equilateral triangle the orthocenter, centroid, circumcenter and incenter are in the same spot

The center of the circle is the centroid and height match with the median. The radius of the circumcircle is equal to two thirds the height.

Formula for the Radius of the circumcircle = 2/3 h

= 2/3 x √3 /2 (15)

= 5 √3 cm (=radius)

Area of the circle = πr^

= 3.14 x( 5 √3 ) ^

=3.14 x(25*3)

=3.14 x 75

=235.5

=236 cm²

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