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Talja [164]
2 years ago
15

Mr. See weights his grades. Tests are worth 60%, quizzes are worth 25% and homework is 15%. Joey's test average is an 82, his qu

iz average is a 77, and his homework average is a 98. What is Joey's current grade?
Mathematics
1 answer:
goldenfox [79]2 years ago
4 0

Answer:

83.15

Step-by-step explanation:

Joey's current grade can be determined by weighting his scores with the weights given and adding the results

Tests = 0.6 x 82 = 49.2

Quizzes = 0.25 x 77 = 19.25

homework = 0.15 x 98 = 14.7

49.2 + 19.25 + 14.7 = 83.15

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bagirrra123 [75]

Answer: -2

Step-by-step explanation:

The information in the question can be used to form an equation which goes thus:

2nd term = a + d = 4 ...... i

5th term = a + 4d = 22 ....... ii

From equation i

a = 4 - d ........ iii

Put equation iii into ii

a + 4d = 22

(4 - d) + 4d = 22

4 - d + 4d = 22

4 + 3d = 22

3d = 22 - 4

3d = 18

d = 18/3

d = 6

Commons difference is 6

Since a + d = 4

a + 6 = 4

a = 4 - 6

a = -2

The first term is -2

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3 years ago
Kyra was building a bed for her dollhouse. She used her bed, which is 4 feet × 5 feet, as a guide. She scaled down the dimension
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The dimensions would have to be 20 x 5 as the model holds the same amount for each side, and because 5 is larger than 4 its used as the models stand.
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3 years ago
Find the center and radius of (x + 9)^2 + (y + 6)^2 = 9.
VARVARA [1.3K]
You can do this by comparing your equation to the general form of equation of a circle

( x - a)^2 + (y - b)^2 = r^2       where (a,b) is the centre and r = radius:-
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so (a,b) = (-9,-6)  and r = 3

so the answer is B
4 0
3 years ago
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Andre45 [30]

Answer:

The pair of slacks would be

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Step-by-step explanation:

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I need help fast!!!!!!!!!!!!!
storchak [24]

Answer:

The answer is 140

Step-by-step explanation:

When the total measurements of the six-shaped corners is equal 720

Then x equal to

x = 720 - (120 + 120 + 120 + 130 + 90) = 140

If you need any explanation in it or anything on math you can communicate with me on Whats on this number +201557831028 or in email or face or anything

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