From a shipment of 400 light-bulbs, a sample of 80 was selected at random and tested. If 32 light-bulbs in the sample were found
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Answer:
Savings on electricity per year by brand B = 114.3 - 104.76 = $9.54
Step-by-step explanation:
Ms. Wang is shopping for a new refrigerator. Brand A costs $569 and uses 635 kilowatt-hours per year. Brand B costs $647 and uses 582 kilowatt-hours per year.
Let's assume he buys brand B, so he already has a loss over the price of the commodity that is , loss = 647 - 569 =$78
Cost of electricity = $0.18
Now in the case of electricity,
spending on Brand A = 635 0.18 = $114.3
spending on Brand B = 582 0.18 = $104.76
Savings on electricity per year by brand B = 114.3 - 104.76 = $9.54