X = (12/5,0)
y = (0,-4)
substitute 0 in for y & solve for x , to find the y-intercept substitute 0 in for x and then solve . ( I hope that makes sense)
10.5 small boxes equals the same amount of cereal in a large box
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How to determine the value</h3>
From the information given, let:
n is the number of smaller boxes
We know that:
Then,
12 + 7.6n = 6 + 8n
collect like terms
8n - 7. 6n = 12 - 6
0. 4n = 6
n = 6/ 0. 4
n = 15
The amount of cereal in a large box is;
6 + 8n = 6 + 8 (15) = 126 ounces
The amount of cereal in the smaller box is 12 ounces
Divide the volume of the larger box by the volume of the smaller box;
= 126/ 12
= 10. 5 smaller boxes
Hence, 10.5 small boxes equals the same amount of cereal in a large box
The complete question:
A cereal box manufacturer changes the sizeof the box to increase the amount of cereal it contains. The equations 12 + 7.6n and 6 + 8n, where n is the number of smaller boxes, are both representative of the amount of cereal that the new larger box contains. How many smaller boxes equal the same amount of cereal in the larger box?
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10. As 8x = 2x + 60. So x =10
#1. look at the individual probability first.
A dice has 6 sides. The numbers > 2 are {3, 4, 5, 6}. So the chance of rolling a number > 2 is 4/6 or 2/3 simplified.
Multiples of 3 on a dice are {3, 6}. So the chance of rolling a multiple of 3 is 2/6 or 1/3 simplified.
Rolling a dice is an independent event, like flipping a coin the previous roll does not have an effect on the outcome of the next roll. So when you see the word AND connecting the outcomes, you multiply them.
Prob of rolling >2 AND then multiple of 3 = (2/3)*(1/3)
= 2/9
#2. The total socks in the drawer: 8+8+4= 20 socks
The probability of first drawing a blue sock is 8/20 or 2/5 simplified.
Since the question does not say the socks are put back in the drawer, the total number of socks and number of blue socks decrease by 1 after the first draw. This makes the next draw dependent on the first.
The probability of drawing a blue sock is then: 7/19
because there's a blue sock missing.
Probability of drawing blue sock AND then a blue sock (without replacement)
= (2/5)*(7/19)
= 14/95
Answer:
it depends on how many females are there
Step-by-step explanation:
I need to know how many females are there
