3 packs of soda cost $10 less than 5 packs of soda. Write an equation and solve to find the cost of one pack of soda *
2 answers:
Answer:
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Step-by-step explanation:
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Answer:
3x=5x-10
Step-by-step explanation:
The first thing we must do is define a variable.
We have:
x: unit cost of each pack of soda
We now write the equation that models the problem.
We know that:
3 packs of soda cost $ 10 less than 5 packs of soda.
Which then another way to write this is- 1 pack cost $5
3x=5x-10 (br)
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400 quarters
$1 = 4q
4q • 100 = 400
400q=$100
Answer:
![sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cot(2\alpha ) = \frac{16511}{18720}](https://tex.z-dn.net/?f=sin%282%5Calpha%20%29%3D2%28%5Cfrac%7B5%7D%7B12%7D%29%28%5Cfrac%7B12%7D%7B13%7D%29%3D%5Cfrac%7B10%7D%7B13%7D%5C%5Ccot%282%5Calpha%20%29%20%3D%20%5Cfrac%7B16511%7D%7B18720%7D)
Step-by-step explanation:
![\text{if } cos(\alpha)=\frac{12}{13}\\\text{That must mean we have a triangle with base 12, and hypotenuse 13.}\\\text{Using Pythagoras, we can determine the base of the triangle must be 5.}\\a^2+b^2=c^2 \text{, where c is the hypotenuse and a, b are the two other sides.}\\c^2-b^2=a^2\\\sqrt{c^2-b^2}=a\\\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5\\\text{Therefore, }sin(\alpha) = \frac{5}{12}\\sin(2\alpha)=2sin(\alpha )cos(\alpha)\\\text{(From double angle formulae identities)}\\](https://tex.z-dn.net/?f=%5Ctext%7Bif%20%7D%20cos%28%5Calpha%29%3D%5Cfrac%7B12%7D%7B13%7D%5C%5C%5Ctext%7BThat%20must%20mean%20we%20have%20a%20triangle%20with%20base%2012%2C%20and%20hypotenuse%2013.%7D%5C%5C%5Ctext%7BUsing%20Pythagoras%2C%20we%20can%20determine%20the%20base%20of%20the%20triangle%20must%20be%205.%7D%5C%5Ca%5E2%2Bb%5E2%3Dc%5E2%20%5Ctext%7B%2C%20where%20c%20is%20the%20hypotenuse%20and%20a%2C%20b%20are%20the%20two%20other%20sides.%7D%5C%5Cc%5E2-b%5E2%3Da%5E2%5C%5C%5Csqrt%7Bc%5E2-b%5E2%7D%3Da%5C%5C%5Csqrt%7B13%5E2-12%5E2%7D%3D%5Csqrt%7B169-144%7D%3D%5Csqrt%7B25%7D%3D5%5C%5C%5Ctext%7BTherefore%2C%20%7Dsin%28%5Calpha%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D%5C%5Csin%282%5Calpha%29%3D2sin%28%5Calpha%20%29cos%28%5Calpha%29%5C%5C%5Ctext%7B%28From%20double%20angle%20formulae%20identities%29%7D%5C%5C)
![sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cos(2\alpha )=cos^2(\alpha)-sin^2(\alpha)\\cos(2\alpha )=(\frac{12}{13})^2-(\frac{5}{12})^2=\frac{16511}{24336}\\cot(2\alpha)=\frac{cos(2\alpha)}{sin(2\alpha)}=\frac{\frac{16511}{24336}}{\frac{10}{13}}=\frac{16511}{18720}](https://tex.z-dn.net/?f=sin%282%5Calpha%20%29%3D2%28%5Cfrac%7B5%7D%7B12%7D%29%28%5Cfrac%7B12%7D%7B13%7D%29%3D%5Cfrac%7B10%7D%7B13%7D%5C%5Ccos%282%5Calpha%20%29%3Dcos%5E2%28%5Calpha%29-sin%5E2%28%5Calpha%29%5C%5Ccos%282%5Calpha%20%29%3D%28%5Cfrac%7B12%7D%7B13%7D%29%5E2-%28%5Cfrac%7B5%7D%7B12%7D%29%5E2%3D%5Cfrac%7B16511%7D%7B24336%7D%5C%5Ccot%282%5Calpha%29%3D%5Cfrac%7Bcos%282%5Calpha%29%7D%7Bsin%282%5Calpha%29%7D%3D%5Cfrac%7B%5Cfrac%7B16511%7D%7B24336%7D%7D%7B%5Cfrac%7B10%7D%7B13%7D%7D%3D%5Cfrac%7B16511%7D%7B18720%7D)
It would be 37’000 because 20% of 185000 is 37’000 which you get by 20 x 185000 and dividing the answer to 100.
Answer:
y = 2
Step-by-step explanation:
Since the line is parallel to the x-axis,
the gradient, m = 0
From the point, we know that
x = 5
y = 2
So y = 2 is the line that parallel to x-axis
Change 5/3 to 15/9. Then add 15 + 17 and put it over 9. 32/9