1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
grin007 [14]
2 years ago
6

What is the range of this function 6 goes to 5 8 goes to -3 10goes to -8 and 12 goes to 7

Mathematics
1 answer:
sattari [20]2 years ago
3 0

Answer:

C, {-8, -3, 5, 7}

Step-by-step explanation:

the range = the y-coordinates

i hope this helps you

You might be interested in
Answer correctly and ASAP PLEASE!!
slamgirl [31]

Answer:

19 members

Step-by-step explanation:

54 / 2 = 227

27 / 3 = 9

9-1 = 8

27 - 8 = 19

19

7 0
3 years ago
No files just type it in
larisa86 [58]

( 3 × 5 ) + ( 2 × 4 ) =

15 + 8 = $ 23

7 0
3 years ago
A banana bread recipe calls for 3/4 cup butte. One tablespoon equals 1/16 cup.How many tablespoons of butter are needed to make
grandymaker [24]
Well if you make 3/4 and 1/16 similar fractions by making 3/4 into 12/16 you get the answer in the numerator which is 12 tbsp of butter
4 0
3 years ago
Alicia drove 265 miles in 5 hours. What is the average rate that she traveled?
Bumek [7]
265/5 = 53/1

53 miles per hour. 

*I hope this helped!
5 0
2 years ago
Read 2 more answers
Number 1d please help me analytical geometry
lesantik [10]
For a) is just the distance formula

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ x}}\quad ,&{{ 1}})\quad 
%  (c,d)
B&({{ -4}}\quad ,&{{ 1}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\sqrt{8} = \sqrt{({{ -4}}-{{ x}})^2 + (1-1)^2}
\end{array}
-----------------------------------------------------------------------------------------
for b)  is also the distance formula, just different coordinates and distance

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ -7}}\quad ,&{{ y}})\quad 
%  (c,d)
B&({{ -3}}\quad ,&{{ 4}})
\end{array}\ \ 
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
4\sqrt{2} = \sqrt{(-3-(-7))^2+(4-y)^2}
\end{array}
--------------------------------------------------------------------------
for c)  well... we know AB = BC.... we do have the coordinates for A and B
so... find the distance for AB, that is \bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ -3}}\quad ,&{{ 0}})\quad 
%  (c,d)
B&({{ 5}}\quad ,&{{ -2}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=\boxed{?}

\end{array}

now.. whatever that is, is  = BC, so  the distance for BC is

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
B&({{ 5}}\quad ,&{{ -2}})\quad 
%  (c,d)
C&({{ -13}}\quad ,&{{ y}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=BC\\\\
BC=\boxed{?}

\end{array}

so... whatever distance you get for AB, set it equals to BC, BC will be in "y-terms" since the C point has a variable in its ordered points

so.. .solve AB = BC for "y"
------------------------------------------------------------------------------------

now d)   we know M and N are equidistant to P, that simply means that P is the midpoint of the segment MN

so use the midpoint formula

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
M&({{-2}}\quad ,&{{ 1}})\quad 
%  (c,d)
N&({{ x}}\quad ,&{{ 1}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=P
\\\\\\


\bf \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=(1,4)\implies 
\begin{cases}
\cfrac{{{ x_2}} + {{ x_1}}}{2}=1\leftarrow \textit{solve for "x"}\\\\
\cfrac{{{ y_2}} + {{ y_1}}}{2}=4
\end{cases}

now, for d), you can also just use the distance formula, find the distance for MP, then since MP = PN, find the distance for PN in x-terms and then set it to equal to MP and solve for "x"


7 0
3 years ago
Other questions:
  • The diameter of the larger circle is 10.5 cm. The diameter of the smaller circle is 4.5 cm. What is the approximate area of the
    12·2 answers
  • There is an average of 3.5×10−2 kilograms of dissolved salt in each liter of seawater.
    14·2 answers
  • Sam is eating a Big Hamburger. The first bite was 20% of the Hamburger, the second bite was 20% of what is left and so every nex
    11·1 answer
  • Write two word sentences for the equation a+15=24. The ... of a and 15....24​
    10·1 answer
  • Question Progress
    12·1 answer
  • In an English test, the mean is 60 and the standard deviation is 6. Assuming the scores are normally distributed, answer the fol
    8·1 answer
  • 10 flowers in 5 vases = ? flowers per vase
    10·2 answers
  • Barry and Lenora were each given the same pair of numbers. Barry's description of the two
    9·1 answer
  • Help, stuck with math
    7·1 answer
  • 5/14 + -14/5<br><br> Can someone please help me I need it quick
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!