Hey there! I'm happy to help!
First, we need to rotate our points 180° about the origin. To find the coordinates after such a rotation, we simply find the negative version of each number in the ordered pair, which can be written as (x,y)⇒(-x,-y).
Let's convert this below
A: (1,1)⇒(-1,-1)
B: (5,4)⇒(-5,-4)
C: (7,1)⇒(-7,-1)
D: (3,-2)⇒(-3,2)
Now, we need to translate these new points five units to the right and one unit down. This means we will add 5 to our x-value and subtract 1 from our y-value. This will look like (x,y)⇒(x+5,y-1). Let's do this below.
A: (-1,-1)⇒(4,-2)
B: (-5,-4)⇒(0,-5)
C: (-7,-1)⇒(-2,-2)
D: (-3,2)⇒(2,1)
Therefore, this new parallelogram has coordinates of A'(4,-2), B'(0,-5), C'(-2,-2), and D'(2,1)
Now you know how to find the coordinates of translated figures! Have a wonderful day! :D
Answer:
- 8x + 9
Step-by-step explanation:
To evaluate g(2x - 1) substitute x = 2x - 1 into g(x), that is
g(2x - 1)
= - 4(2x - 1) + 5 ← distribute parenthesis and simplify
= - 8x + 4 + 5
= - 8x + 9
6 teams 5 times the key word is times this means multiply so 6x5=30
Answer: C. 84
Step-by-step explanation:
In triangles ABD y BCD:
- AD=CD
- Angle BAD = angle BCD
- BD common side
THEN the triangles are equal because they have two sides and the angle opposite the longest side respectively equal.
CBD = ABD = 42 because the triangles ABD y BCD are equal
ABC = CBD+ABD = 42+42= 84
Answer:
See below.
Step-by-step explanation:
Here's an example to illustrate the method:
f(x) = 3x^2 - 6x + 10
First divide the first 2 terms by the coefficient of x^2 , which is 3:
= 3(x^2 - 2x) + 10
Now divide the -2 ( in -2x) by 2 and write the x^2 - 2x in the form
(x - b/2)^2 - b/2)^2 (where b = 2) , which will be equal to x^2 - 2x in a different form.
= 3[ (x - 1)^2 - 1^2 ] + 10 (Note: we have to subtract the 1^2 because (x - 1)^2 = x^2 - 2x + 1^2 and we have to make it equal to x^2 - 2x)
= 3 [(x - 1)^2 -1 ] + 10
= 3(x - 1)^2 - 3 + 10
= <u>3(x - 1)^2 + 7 </u><------- Vertex form.
In general form the vertex form of:
ax^2 + bx + c = a [(x - b/2a)^2 - (b/2a)^2] + c .
This is not easy to commit to memory so I suggest the best way to do these conversions is to remember the general method.
