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aleksandrvk [35]
3 years ago
14

Is the statement true or false? If false, give a counterexample.

Mathematics
1 answer:
scoundrel [369]3 years ago
6 0

Answer:

D. false; if a = 1, b = 2, and c = 3, then 1(2 + 3) ≠ 1(2) + 2(3)

Step-by-step explanation:

A is false, because the a is being distributed/ being multiplied to all terms inside the parenthesis, and not the term b.

B is also false. There is no indicated negative signs.

C is also false because 1(1 + 1) is EQUAL to 1(1) + 1(1)

D is true.

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In 1986, the worst nuclear disaster occurred in Chernobyl, USSR, when an explosion at a nuclear power plant released 1000 kg of
Lostsunrise [7]

Considering the function for the remaining amount of cesium in the atmosphere, F(x) = 1000×0.5^(x/30), we have;

First part:

  • The area will be safe again in about 100 years time.

Second part;

  • The y-intercept is at the start of the measurement

Third part;

  • The function is a decay function

<h3>Which method can be used to evaluate the given function?</h3>

First part;

The given function for the remaining amount of cesium is presented as follows;

F(x) = 1000 \times  {0.5}^{ \frac{x}{30} }

When 100 kg. of cesium is remaining, we have;

100= 1000 \times  {0.5}^{ \frac{x}{30} }

Which gives;

\frac{x}{30}  =  \frac{ log(0.1) }{ log(0.5) }

x=  \frac{ log(0.1) }{ log(0.5) }  \times 30 \approx  100

  • Therefore, the area will be safe again in approximately 100 years.

Second part;

The y-intercept is given by the point where <em>x </em>= 0

At the y-intercept, we therefore have;

F(0) = 1000 \times  {0.5}^{ \frac{0}{30} }

  • F(0) = 1000

At the y-intercept, the amount of cesium remaining, F(x) is 1,000, which is the initial amount of cesium.

  • The y-intercept is therefore, at the start of the measurement, where 1000 kg. is present in the atmosphere.

Third part;

The amount of cesium remaining F (x) decreases as the time, <em>x</em>, increases, the function is therefore a decay function.

Learn more about exponential functions here;

brainly.com/question/2456547

#SPJ1

8 0
2 years ago
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