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3 years ago

Is the statement true or false? If false, give a counterexample.

Mathematics

1 answer:

scoundrel [369]3 years ago

6 0

Answer:

D. false; if a = 1, b = 2, and c = 3, then 1(2 + 3) ≠ 1(2) + 2(3)

Step-by-step explanation:

A is false, because the a is being distributed/ being multiplied to all terms inside the parenthesis, and not the term b.

B is also false. There is no indicated negative signs.

C is also false because 1(1 + 1) is EQUAL to 1(1) + 1(1)

D is true.

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Simplify 6 (3 5/6 - 1 1/4)<br>

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

6(3 5/6 -1 1/4)

3 5/6 - 1 1/4 =

3 10/12 - 1 3/12 =

2 7/12 * 6 =

(24+7/12 =

31/12*6)

186/12=

15 1/2

(12*15 =180 186-180=6 [15 6/12 = 15 1/2])

Edit: Steps janky

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2 years ago

What is a difference of squares that has a factor of x + 8?

Goshia [24]

Hello,

x²-64=(x+8)(x-8)
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3 years ago

3a. Write an equation in slope-intercept form of a<br> line that passes through (2,1) and (6,-5).

eimsori [14]

Answer:

$y =- 3/2x + 4$

Step-by-step explanation:

$(2,1) and (6,-5).\\x_1 = 2\\x_2 = 6\\y_1 =1\\y_2 =-5\\\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\\ \\\frac{y-1}{x-2} = \frac{-5-1}{6-2}\\\\\frac{y-1}{x-2} = \frac{-6}{4} \\Cross-Multiply\\4(y-1) = -6(x-2)\\4y-4=-6x+12\\4y =-6x+12+4\\4y = -6x+16\\Divide- through-by ; 4\\\frac{4y = -6x+16}{4} \\\\y = -\frac{3}{2} x +4$

5 0

3 years ago

Sophia can walk 1.4 miles in 15 minutes. At this rate how far can she walk in an hour

spin [16.1K]

At this rate she can walk 5.6 miles because you need to multiply 1.4 by each 15 minutes until it gets to a hour so you get 5.6 miles

6 0

3 years ago

Read 2 more answers

Kirby is four miles from the train station, from which a train is due to leave in 56 minutes. Kirby is walking along at 3 mph, a

Luda [366]

Let's assume that Kirby walks with a speed
$v_1 = 3 mph$
for a time $t_1$ , and that he runs with a speed
$v_2 = 12 mph$
for a time $t_2$ .

The total time available for Kirby to catch the train is:
$t=56 min = 0.93 h$
and this must be equal to the sum of the two times t1 and t2:
$0.93 = t_1 + t_2$

The distance Kirby should cover is
$S=4 m$
and this should be equal to the sum of the distances covered by walking and by running:
$4 = S_1 + S_2 = v_1 t_1 + v_2 t_2 = 3 t_1 + 12 t_2$

So we have a system of 2 equations:
$0.93 = t_1 + t_2$
$4 = 3 t_1 + 12 t_2$

If we solve the system, we find:
$t_1 = 0.80 h = 48 min$
$t_2 = 0.13 h = 8 min$

So, Kirby needs to run at least for 8 minutes in order to catch the train.

6 0

3 years ago