(2) So we know Ethan uses 1/4 cup of milk for his cake. And if he needs to make 3 times the amount of 1 cake, he'll make 3 cakes today. So we multiply the amount of cakes (3) by the amount of milk needed (1/4)
3 * 1/4 = 3/4
Ethan will need 3/4 cups of milk.
(3) We know Isabella need's 2/5 of a gallon of the food to make 1 gallon.
She want's to make 5 gallons, so like the other problem, we multiply the amount of gallons (5) by the amount of food needed (2/5):
5 * 2/5 = 10/5 = 2/1.
Isabella will need 2 gallons of food.
Answer:
a) The Venn diagram is presented in the attached image to this answer.
b) 0.82
c) 0.16
Step-by-step explanation:
a) The Venn diagram is presented in the attached image to this answer.
n(U) = 100%
n(S) = 48%
n(B) = 66%
n(H) = 38%
n(S n B) = 30%
n(B n H) = 22%
n(S n H) = 28%
n(S n B n H) = 12%
The specific breakdowns for each subgroup is calculated on the Venn diagram attached.
b) The probability that a randomly selected student likes basketball or hockey.
P(B U H)
From the Venn diagram,
n(B U H) = n(S' n B n H') + n(S' n B n H) + n(S n B n H') + n(S n B n H) + n(S n B' n H) + n(S' n B' n H) = 26 + 10 + 18 + 12 + 16 + 0 = 82%
P(B U H) = 82/100 = 0.82
c) The probability that a randomly selected student does not like any of these sports.
P(S' n B' n H')
n(S' n B' n H') = n(U) - [n(S' n B n H') + n(S' n B n H) + n(S n B n H') + n(S n B n H) + n(S n B' n H) + n(S' n B' n H) + n(S n B' n H')]
n(S' n B' n H') = 100 - (26 + 10 + 18 + 12 + 16 + 0 + 2) = 100 - 84 = 16%
P(S' n B' n H') = 16/100 = 0.16
The area of the sector, to 4 decimal places, is 78.6794 cm².
We have given that,
Sector Area= ( angle of sector/360). R2
We have to determine the Sector Area
<h3>What is the Area of a Sector of a Circle?</h3>
Area of sector = ∅/360 × πr².
We have given the following:
∅ = 46°
Radius (r) = 14 cm
Area of sector = 46/360 × π(14²)
Area of sector ≈ 78.6794 cm²
The area of the sector is approximately 78.6794 cm².
Learn more about the area of the sector on:
brainly.com/question/8159268
#SPJ1
<h3>Answer</h3>
Page No 7.13:
Question 1:
Add the following:
(i) 3x and 7x
(ii) −5xy and 9xy
ANSWER:
We have
(i) 3x + 7x = (3 + 7)x = 10x
(ii) -5xy + 9xy = ( -5 + 9)xy = 4xy