What is the equation of the line

Which trigonometric function would you use to solve the problem?

umka21 [38]

you would use tan or cot

3 0

3 years ago

? ( Ellen has 2 quarters 1 dime and 1 nickel how many different amounts of money can you make using 1 ore more of these clubs )

ohaa [14]

the answer to this is nine

7 0

3 years ago

Plz, Help me with this!!!!

yanalaym [24]

It’s 152y+125, basically by simplifying

6 0

2 years ago

Read 2 more answers

An exponential function is expressed in the form y=axb^x. The relation represents a growth when _______ and a decay when ______.

seropon [69]

Answer:

Growth when: b>1.

Decay when: 0<b<1.

Step-by-step explanation:

Any function in the form $f(x)=a{\times}b^x$ , where a > 0, b > 0 and b not equal to $1$ is called an exponential function with base b.

If 0 < b < 1 this is an example of an exponential decay.

The general shape of an exponential with b > 1 is an example of exponential growth.

Hence,

An exponential function is expressed in the form $f(x)=a{\times}b^x$ , The relation represents a growth when b >1 and a decay when 0<b<1.

5 0

2 years ago

The coordinates of point A are (p, q) and coordinates of point B are (p+2q, q+2p). Provide your complete solutions and proofs in

Dafna1 [17]

Answer:

The mid-point (p + q , q + p) of AB is the same distance from the x-axis and the y-axis

Step-by-step explanation:

* Lets explain how to solve the problem

- Any point will be equidistant from the x-axis and the y-axis must have

equal coordinates

- Ex: point (4 , 4) is the same distance from the x-axis and the y-axis

because the distance from the x-axis to the point is 4 (y-coordinate)

and the distance from the y-axis and the point is 4 (x-coordinate)

- If (x , y) is the mid-point of a segment its endpoints are

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then

$x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

* Lets solve the problem

∵ Point A has coordinates (p , q)

∵ Point B has coordinates (p + 2q , q + 2p)

- The mid-point of AB is (x , y)

∵ $x=\frac{p+p+2q}{2}$

∴ $x=\frac{2p+2q}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $x=\frac{2(p+q)}{2}$

- Divide up and down by 2

∴ x = p + q

∵ $y=\frac{q+q+2p}{2}$

∴ $y=\frac{2q+2p}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $y=\frac{2(q+p)}{2}$

- Divide up and down by 2

∴ y = q + p

∴ The mid point of AB is (p + q , q + p)

- p + q is the same with q + p

∵ The x-coordinate of the mid point of AB is p + q

∵ The y-coordinate of the mid point of AB is q + p

∵ p + q = q + p

∴ The coordinates of the mid-point of AB are equal

- According the explanation above

∴ The mid-point (p + q , q + p) of AB is the same distance from the

x-axis and the y-axis

8 0

3 years ago