Answer: 6.8571 (Round as needed)
Hope this is correct
Step-by-step explanation:
This is a simple ratio problem
Using the similarity statement we can say 14:12, (ab:pq)
That is our ratio.
So we do 14/12 = 8/x, we solve this using algebra to get our answer.
Hope this is correct.
This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
1) Correct.
2) The y-intercept is when x=0, so it is (0,5).
To solve this, first we calculate all the total cost of
the items that is:
total cost = $14.96 + $19.87 + $5.37
total cost = $40.20
So we see that the actual cost is similar with the
estimate so his calculation is reasonable.
