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stealth61 [152]
3 years ago
10

A polynomial of degree 4 in y has at most

Mathematics
2 answers:
klemol [59]3 years ago
8 0

Answer:

A

Step-by-step explanation:

the keyword is degree 4 which means it has four terms

Kitty [74]3 years ago
5 0

Answer:

C.

Step-by-step explanation:

The highest term must be of x^4, then decreasing to x^3, x^2, x and the constant term.

Altogether there are at maximum 5 terms.

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Which is greater .83 or .083?
Serggg [28]
.83 is greater .038 is in the thousands place and .83 is in the hundreds hope this Helped :D
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What is the value of a?<br><br><br><br><br> 27.5<br><br><br> 45<br><br><br> 90<br><br><br> 50
Valentin [98]
90. The measure of an inscribed angle is half of that of the measure of its arc, and the measure of the angle corresponding with arc a is 45. 45*2 is 90, so 90 is the measure of arc a.
7 0
3 years ago
Read 2 more answers
The mass of the moon is 7.36*10^25 grams to the nearest tenth how many moons would it take to equal the mass of earth
trapecia [35]

Nearly 81 moons will be required to equate the mass of moon to the mass of earth.

Step-by-step explanation:

Mass of earth is 5.972*10^24 kg.  

Mass of the moon is 7.36*10^25 g = 7.36*10^22 kg

As mass of the Earth is given as 5.972 * 10^24 kg and mass of the moon is given as 7.36 * 10^22 kg, then the number of moons required to make it equal to the mass of earth can be calculated by taking the ratio of mass of earth to moon.

 Mass of Earth = Number of moons * Mass of Moon

Number of Moons = Mass of Earth/Mass of moon

Number of moons = 5.972 * 10^24/7.36*10^22= 81 moons.

So nearly 81 moons will be required to equate the mass of moon to the mass of earth.

6 0
3 years ago
Evaluation the expression using a model 2/3 dived by 1/2.
m_a_m_a [10]

Answer:la respuesta es 8/0

Step-by-step explanation:

8 0
3 years ago
Identify the GCF of 6x^2y^2 − 8xy^2 + 10xy
myrzilka [38]

Answer:

The GCF for the numerical part is 2

Step-by-step explanation:

6x^2y^2-8xy^2+10xy

It contains both numbers and variables, there are two steps to find the GCF(HCF).

1). Find the GCF for the numerical part 6, -8,10

2). Find the GCF for the variable part x^2,y^2,x^1,y^2,x^1,y^3

3).Multiply the values together.

Find the common factors for the numerical part:

6,-8,10

Factors of 6

6: 1,2,3,6

Factors of -8

-8: -8,-4,-2,-1,1,2,4,8

Factors of 10

10:1,2,5,10

Common factors of 6,-8, 10 are 1,2

The GCF Numerical=2

The GCF Variable= xy^2

Multiply the GCF of the numerical part 2 and the GCF of the variable part xy^2, and you'll get 2xy^2

6 0
2 years ago
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