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trapecia [35]
3 years ago
8

HELP DUE NOW! BRANLIEST AND LOTS OF PONTS

Mathematics
2 answers:
algol [13]3 years ago
5 0

Answer:

please don't waste your points I request you...

Lisa [10]3 years ago
4 0

Answer:

I think it’s a

Step-by-step explanation:

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What is the simplified value of the exponential expression 27 1/3?<br> 1/3<br> 1/9<br> 3<br> 9
madreJ [45]

Answer:

Step-by-step explanation:

27^1/3

27 is cube root of 3

so it can also be written as (3)^3

∴ {(3)^3}^1/3

3 and 3 will get cancelled

so it will be 3^1

= 3

8 0
3 years ago
I will give brainiest to whoever answers correctly !!
evablogger [386]

Answer:

markup=62 %

Step-by-step explanation:  

4 0
3 years ago
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The graph of f(x) = (0.5)x is replaced by the graph of g(x) = (0.5)x − k. If g(x) is obtained by shifting f(x) down by 5 units,
tekilochka [14]

Answer: The value of k is 5 units.

Step-by-step explanation:

Since we have given that

The graph of f(x)=0.5x is replaced by the graph of g(x) = 0.5x-k

If g(x) is obtained by shifting f(x) down by 5 units,

Then the graph of f(x) = 0.5x is replaced by the graph of g(x) = 0.5x-5

Hence, k = 5 units

Therefore, the value of k is 5 units.

7 0
3 years ago
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Can someone help me again please. I will pay extra fr please
fgiga [73]

Answer:

y = 3x + 3

Step-by-step explanation:

First, you check for the y-intercept, which is 3 for this equation.

In order to find the slope, pick two points and apply the slope formula.

I would just use rise/run. The slope should be 3/1.

3 0
2 years ago
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Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
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