Answer:
Step-by-step explanation:
27^1/3
27 is cube root of 3
so it can also be written as (3)^3
∴ {(3)^3}^1/3
3 and 3 will get cancelled
so it will be 3^1
= 3
Answer:
markup=62 %
Step-by-step explanation:
Answer: The value of k is 5 units.
Step-by-step explanation:
Since we have given that
The graph of f(x)=0.5x is replaced by the graph of g(x) = 0.5x-k
If g(x) is obtained by shifting f(x) down by 5 units,
Then the graph of f(x) = 0.5x is replaced by the graph of g(x) = 0.5x-5
Hence, k = 5 units
Therefore, the value of k is 5 units.
Answer:
y = 3x + 3
Step-by-step explanation:
First, you check for the y-intercept, which is 3 for this equation.
In order to find the slope, pick two points and apply the slope formula.
I would just use rise/run. The slope should be 3/1.
<h3>Answer:</h3>
Equation of the ellipse = 3x² + 5y² = 32
<h3>Step-by-step explanation:</h3>
<h2>Given:</h2>
- The centre of the ellipse is at the origin and the X axis is the major axis
- It passes through the points (-3, 1) and (2, -2)
<h2>To Find:</h2>
- The equation of the ellipse
<h2>Solution:</h2>
The equation of an ellipse is given by,

Given that the ellipse passes through the point (-3, 1)
Hence,

Cross multiplying we get,
- 9b² + a² = 1 ²× a²b²
- a²b² = 9b² + a²
Multiply by 4 on both sides,
- 4a²b² = 36b² + 4a²------(1)
Also by given the ellipse passes through the point (2, -2)
Substituting this,

Cross multiply,
- 4b² + 4a² = 1 × a²b²
- a²b² = 4b² + 4a²-------(2)
Subtracting equations 2 and 1,
- 3a²b² = 32b²
- 3a² = 32
- a² = 32/3----(3)
Substituting in 2,
- 32/3 × b² = 4b² + 4 × 32/3
- 32/3 b² = 4b² + 128/3
- 32/3 b² = (12b² + 128)/3
- 32b² = 12b² + 128
- 20b² = 128
- b² = 128/20 = 32/5
Substituting the values in the equation for ellipse,


Multiplying whole equation by 32 we get,
3x² + 5y² = 32
<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>