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ipn [44]
3 years ago
8

A tortoise and hare are competing in a race. The function f and g are such that f(t) represents the tortoise's distance from the

finish line (in meters) t seconds after the start of the race and g (t) represents the hare's distance from the finish line (in meters) t seconds after the start of the race.
If we want to compute the number of seconds needed for the hare to finish the race, which of the following procedures should be used?
A. Solve g(t)=0 for the value of t.
B. Solve g(t)=1000 for the value of t.
C. Evaluate g(0).
D. Solve f(t)=g(t) for the value of t.
E. Evaluate g(1000).
Mathematics
1 answer:
Pepsi [2]3 years ago
7 0

Answer:

g(t) = 0; solve for t

Step-by-step explanation:

Given

Options (a) to (e)

Required

Which of the options is true

From the question, we understand that: g(t) represents hare's time to complete the race

At the beginning of the race, the time left to complete the race is at g(t) = 0; then solve for t.

<u>Take for instance:</u>

g(t) = 10 - t

The time to complete the race is: g(t) = 0

So, we have:

0 = 10 - t

Collect like terms

t = 10

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Oksana_A [137]

2^2-28

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that is it

4 0
3 years ago
What would be the answer to this question?
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3 0
3 years ago
Calculate the Laplace transforms of the following from the definition. 1. y = t^2. y = t^3
Likurg_2 [28]

Answer:

1) L(y)=\frac{2}{s^{3}}

2) L(y)=\frac{6}{s^{4}}

Step-by-step explanation:

To find : Calculate the Laplace transforms of the following from the definition ?

Solution :

We know that,

Laplace transforms of t^n is given by,

L(t^n)=\frac{n!}{s^{n+1}}

1) y=t^2

Laplace of y,

L(y)=L(t^2) here n=2

L(y)=\frac{2!}{s^{2+1}}

L(y)=\frac{2}{s^{3}}

2) y=t^3

Laplace of y,

L(y)=L(t^3) here n=3

L(y)=\frac{3!}{s^{3+1}}

L(y)=\frac{3\times 2}{s^{4}}

L(y)=\frac{6}{s^{4}}

5 0
3 years ago
Brandon is shopping at Old Navy during a sale. All shorts are $16 each and all t-shirts are $10 each.He has $100 to spend and wo
DaniilM [7]
Let
x = the number of shorts bought
y =  the number of t-shirts bought

A pair of shorts costs $16 and a t-shirt costs $10. Brandom has $100 to spend.
Therefore
16x + 10y ≤ 100
This may be written as
y ≤ - 1.6x + 10                 (1)

Brandon wants at least 2 pairs of shorts. Therefore
x ≥ 2                               (2)

Graph the equations y = -1.6x + 10 and  x = 2.
The shaded region satisfies both inequalities.

Answer:
Two possible solutions are
(a) 3 pairs of shorts and 4 t-shirts,
(b) 4 pairs of shorts and 2 t-shirts.

7 0
3 years ago
chad buys peanut in 2-pound bags.He repackages them into bags that hold 5/6 pound of peanuts.How many 2-pound bags of peanuts sh
Nataliya [291]
First, let's find out how many 5/6 pound bags he can fill with on 2 pound bag.

2 divided by 5/6
2 x 6/5
2.4

He can fill 2.4 bags with one 2 bag.
Now we just need to multiply 2.4 by a number that will make it a whole number. You can use the guess and check method starting with 2 to figure your answer out, but 2.4 x 5 = 12 which is a whole number.

This means that Chad needs to buy 5 of the 2 pound bags to fill 12 of the 5/6 pound bags, and he will not have peanuts leftover

6 0
3 years ago
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