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s344n2d4d5 [400]
3 years ago
7

In this triangle, which of the following is true?

Mathematics
2 answers:
AleksAgata [21]3 years ago
8 0

Answer:

Option C. x = 55° and a = 11.47 is the correct option.

Step-by-step explanation:

As we know sum of all angles of a triangle = 180°

Therefore in the triangle given

35° + 90° + x = 180°

125° + x = 180°

x = 180° - 125° °°

x = 55°

Now we we find the sine of 35°

sin35° = \frac{\text{Height}}{\text{Hupotenuse}}

sin35°=\frac{a}{20}

0.5736 = \frac{a}{20}

a = 20×0.5736

a = 11.47 units

Therefore, option C. x = 55° and a = 11.47 is the correct option.

Dvinal [7]3 years ago
3 0
In this triangle, which of the following is true? Solution is attached.

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Leviafan [203]

Answer:

42 i think

Step-by-step explanation:

7 0
2 years ago
Please help this hurts
Svetllana [295]

Answer:

6x - 11y = -13 is the answer.

Step-by-step explanation:

Let's plug in the points to see what sticks.

Start with (-4, -1)

1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 \neq 13

2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13

3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 \neq 17

4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 \neq 13

The only one that fits is #2.  Let's try the other point to be sure.

2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13

3 0
3 years ago
Bob's age is 4 times greater than Susanne's age. Dakota is three years younger than Susanne. The sum of Bob's, Susanne's, and Da
belka [17]
Susanne is 16 years old.

b = Bob's age

s = Susanne's age

d = Dakota's age

Bob's age is 4 times greater than Susanne's age:

b = 4s

Dakota is three years younger than Susanne:

d = s - 3

The sum of Bob's, Susanne's, and Dakota's ages is 93:

b + s + d = 93


 solve these equations:

b = 4s

d = s - 3

b + s + d = 93


and get:

b = 64 years

s = 16 years

(remember that s = Susanne) 

d = 13 years
5 0
3 years ago
A rubber ball is filmed as it bounces on a sidewalk at 25 frames every second. Predict how many seconds of film will be shown in
ANEK [815]
If for one second we have to reserve 25 frames to find length of the movie we have to divide 1750 by 25, so
1750:25=70 [seconds] - its the result

To better understand lets think that u have 8 piece of cake and u want to give every person 2 piece. To find how many person u can invite u can divide 8 by 2. The answer is 4 here ofc.
8 0
3 years ago
Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.
VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let \mu = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, H_0 : \mu \geq 30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, H_A : \mu < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean commute time = 27.6 minutes

            s = sample standard deviation = 19.6 minutes

            n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u>  =  \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }  ~ t_4_9_9

                                       =  -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0
4 years ago
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