Answer:
Part 15) The next three terms are 5/8,3/4 and 7/8
Part 16) The 37th term is -35.5
Step-by-step explanation:
we know that
In an <u>Arithmetic Sequence</u> the difference between one term and the next is a constant and this constant is called the common difference (d)
Part 15) Find the next three terms of the arithmetic sequence

so

The common difference is equal to
d=1/8
<u><em>Find the next three terms of the arithmetic sequence</em></u>
<u><em>Find a5</em></u>
----->
<u><em>Find a6</em></u>
----->
<u><em>Find a7</em></u>
----->
therefore
The next three terms are
5/8,3/4 and 7/8
Part 16) what is the 37th term of the arithmetic sequence

so


The common difference is equal to
d=-1.1
We can write an Arithmetic Sequence as a rule

substitute the values

For n=37
substitute



Answer:
c
Step-by-step explanation:
1.
If no changes are made, the school has a revenue of :
625*400$/student=250,000$
2.
Assume that the school decides to reduce n*20$.
This means that there will be an increase of 50n students.
Thus there are 625 + 50n students, each paying 400-20n dollars.
The revenue is:
(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)
3.
check the options that we have,
a fee of $380 means that n=1, thus
250(n+50)(20-n)=250(1+50)(20-1)=242,250 ($)
a fee of $320 means that n=4, thus
250(n+50)(20-n)=250(4+50)(20-4)=216,000 ($)
the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.
Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
Answer:
x = -9/5
y = 16/5
Step-by-step explanation:
-3x-2y=-1 first you need to multiply the numerator by 3 so when adding
4x+6y=12 the y's cancel and you get a single variable
3(-3x-2y=-1) —> -9x - 6y = -3 then you add the like terms
4x+6y=12 —> 4x + 6y = 12
(-9x+4x) + (6y - 6y) = (-3 + 12)
-5x = 9 then you divide by -5
x = -9/5
then you plug this in to either equation
4(-9/5) + 6y = 12
-36/5 + 6y = 12 then you add 36/5 to both sides
6y = 96/5 then you divide by 6
y = 16/5