Convert the repeating decimal into a fraction: 0.555

algol [13]

Answer:

A = 23.6 units^2

Step-by-step explanation:

Let the base be 8 (as shown).

Find the height of the triangle: Find the supplement of the 100 degree angle; it is (180 - 100), or 80 degrees. The side "opposite" this 80-degree angle is the height of the triangle:

height

sin 80 degrees = ---------------

6

and so the height of the triangle is h = 6 sin 80 degrees, or 5.91 units.

The area of the triangle is found using A = (1/2)(base)(height), which here amounts to:

A = (1/2)(8 units)(5.91 units), or

A = 23.64 units^2, or A = 23.6 units^2

3 0

3 years ago

Simplify. <img src="https://tex.z-dn.net/?f=%5Csqrt%7B15%7D" id="TexFormula1" title="\sqrt{15}" alt="\sqrt{15}" align="absmiddle

jolli1 [7]

Answer:

I think its 15.58

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

An equations'system

yaroslaw [1]

$1. \: x = \frac{11}{9} y + \frac{5}{9} \\ x = \frac{5}{6} y + \frac{1}{6} \\ \\ 2. \: x = \frac{3}{2} y + 2 \\ x = \frac{3}{2} y + 2$

3 0

3 years ago

Explain why any of the four operations (+x +) placed between the two terms 5 and-3/(radical sign) 8 will result in an irrational

kompoz [17]

To answer this question we will have to understand the nature of $\sqrt{8}$ .

$\sqrt{8}$ can be rewritten as: $\sqrt{2\times 2\times 2} =2\sqrt{2}$ . Now, $\sqrt{2}$ is an irrational number and thus any of the four operations of addition, multiplication, subtraction or division placed anywhere between any of these terms will always result in an irrational number.

The only way irrational numbers can be made rational is by dividing or multiplying the given irrational number by the same irrational number.

8 0

3 years ago

Anyone, I need help... Just answer the 6 (c)....and also proper working.☺️

Ainat [17]

Answer:

(i) The area of the rabbit cage when the width is 5.2 m is 81.5 m²

(ii) The area of the rabbit cage if Wilson has 40 meters of wire mesh is 75 m²

Step-by-step explanation:

(i) The given relation of the area, A to the width P of the rabbit cage is A = 3·p²

The graph of the function between the values of 0 and 6 inclusive is found as follows;

A, 3·p²

0, 0

1, 1

2, 12

3, 27

4, 48

5, 75

6, 108

Please find attached the graph of A to 3·p²

From the graph, we have when the the width, p, of the rabbit cage = 5.2, the area, A ≈ 81.5 m²

The area of the rabbit cage when the width is 5.2 m = 81.5 m²

(ii) Also from the graph given that the total wire mess with Wilson = 40 meters, we have;

The formula for the perimeter of the cage = The formula for the perimeter of a rectangle = 2×length + 2×width

The formula for the perimeter of the cage = 2×3×p + 2× p = 8·p

Where the total length of the wire mesh available = 40 meters for the cage

The 40 meters of wire mesh will be used round the perimeter of the cage

∴ 40 m. = 8·p

p = 40/8 = 5 m.

At p = 5 m. the area is given as A = 75 m².

Therefore, the area of the rabbit cage if Wilson has 40 meters of wire mesh = 75 m².

5 0

3 years ago