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Xelga [282]
3 years ago
14

Let f(x) = x2 − 16. Find f−1(x) how you solve this?

Mathematics
1 answer:
SashulF [63]3 years ago
7 0
Let is the answer for the question
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Write an equation for the translation of y = |x|.
lana66690 [7]
B. To translate up or down the number must be outside of the absolute value bars
6 0
3 years ago
Cassie’s plant is growing 5 inches per day, while Jeremy’s plant is growing 6 inches per day. If this pattern were to continue,
LenaWriter [7]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim
Ber [7]

The given function is

f(x)=4\cos \text{(}\pi x)+1

The general form of the cosine function is

y=a\cos (bx+c)+d

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}

The equation of the midline is

y_{ml}=\frac{y_{\max }+y_{\min }}{2}

Since the maximum is at the greatest value of cos, which is 1, then

\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}

Since the minimum is at the smallest value of cos, which is -1, then

\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}

Then substitute them in the equation of the midline

\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0
1 year ago
Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every
Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}

For machine B:

B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }

The <em>bolts</em> unit cancell each other and we are left with <em>seconds</em>

t = \frac{200}{8} s = 25 s

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

Greetings!

4 0
4 years ago
Read 2 more answers
What expression is equivalent
Citrus2011 [14]

Answer:

-4x^2, -3x, -5

Step-by-step explanation:

-4x^2 + 2x - 5 (1 + x)

-4x^2 + 2x - 5 + 5x

-4x^2 - 3x - 5

3 0
3 years ago
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