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Lisa [10]
3 years ago
10

A market sold two packages of sliced beef weighing 1 and one seventh and 4 and one half lb. What was the total weight of the bee

f​?
Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer:

The total weight of the beef sold was 6 11/14 lb.

Step-by-step explanation:

Rewriting this info in a symbolic equation, we get:

2(1 1/7 lb) + 4 1/2 lb.

Perform the multiplication first:  2 2/7 + 4 1/2 (lb)

Here the LCD is 14; 2 2/7 = 16/7; and 4 1/2 = 9/2.

We need to combine 16/7 and 9/2.  Rewriting them using the LCD, we get:

32/14+63/14 = 95/14.  Rewriting this 95/14 as a mixed number, we get:

6.7857 lb (to four decimal places), or 6 11/14 lb.

The total weight of the beef sold was 6 11/14 lb.



Pepsi [2]3 years ago
7 0

Answer:

5 and 9/14

Step-by-step explanation:

convert the numbers into improper fractions

8/7 + 9/2

=

(8 × 2) + (9 × 7)

7 × 2

=

79/14   or 5 and 9/14


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There is 1 brother as they would all have the same brother.
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4 years ago
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Factor the following equation to find its zeros. y = x² - 36
alukav5142 [94]

Answer:

x = 6, x = - 6

Step-by-step explanation:

Given

y = x² - 36

To find the zeros let y = 0, that is

x² - 36 = 0 ← x² - 36 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b), thus

x² - 36 = 0

x² - 6² = 0

(x - 6)(x + 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 6 = 0 ⇒ x = - 6

3 0
3 years ago
What will make this equation true? -3 y=18​
Virty [35]

Answer:

nothing

Step-by-step explanation:

you cant make this equation true!!

8 0
3 years ago
One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.
vampirchik [111]
◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

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5 0
3 years ago
Determine whether each relation is a function. Give the domain and range for each relation.
brilliants [131]

Answer:

Not a function

Domain: {3,4}

Range: {4,5}

Step-by-step explanation:

A function is a relation where each input has its own output. In other words if the x value has multiple corresponding y values then the relation is not a function

For the relation given {(3, 4), (3, 5), (4, 4), (4, 5)} the x value 3 and 4 have more than one corresponding y value therefore the relation shown is not a function

Now let's find the domain and range.

Domain is the set of x values in a relation.

The x values of the given relation are 3 and 4 so the domain is {3,4}

The range is the set of y values in a relation

The y value of the given relation include 4 and 5

So the range would be {4,5}

Notes:

The values of x and y should be written from least to greatest when writing them out as domain and range.

They should be written inside of brackets

Do not repeat numbers when writing the domain and range

3 0
3 years ago
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