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2 years ago

What are the solutions of 16p 2 - 64 = 0?

Mathematics

1 answer:

antoniya [11.8K]2 years ago

4 0

Answer:

=2 =−2

Step-by-step explanation:

<em>Common factor</em>

16 2 − 64 = 0

16(2 − 4)= 0

Use the sum-product pattern

16(2−4)=0

16(2 + 2 − 2 − 4) = 0

Common factor from the two pairs

16(( 2 + 2) + (−2 − 4)) = 0

16 ( ( + 2 ) − 2 ( + 2 ) ) = 0

Rewrite in factored form

16 ( ( + 2 ) − 2 ( + 2 ) ) = 0

1 6 ( − 2 ) ( + 2 ) = 0

Create separate equations

16 ( − 2 ) ( + 2 ) = 0

− 2 = 0

+ 2 = 0

Solve / Rearrange and isolate the variable to find each solution

= − 2

= 2

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2 years ago

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Step-by-step explanation:

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3 years ago

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

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Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

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Similarly, there can be many solutions.

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3 years ago

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arsen [322]

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5 0

2 years ago

Read 2 more answers