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Yakvenalex [24]
3 years ago
6

1 1/2 as a fraction

Mathematics
1 answer:
Alik [6]3 years ago
4 0

Answer:

1.5

Step-by-step explanation:

divide 1/2 and add 1

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Suppose A and B are independent events if P(A) = 0.4 And P(B) = 0.1, what is P(A'uB)? APEX
Aloiza [94]
For Independent Events, P(A) × P(B) = P(A∩B)

so we have, P(A∩B) = 0.4×0.1 = 0.04

P(A') = 1 - 0.4 = 0.6

This information can be represented on a Venn diagram as shown below

P(A'∪B) means the union of everything that is not A with everything that is B

P(A'∪B) = 0.06 + 0.54 + 0.04 = 0.64


5 0
3 years ago
Simplify this algebraic expression completely.<br> 5y- 3(y + 2)
blagie [28]

Distributive property: 5y-3y-6

Combine like terms: 2y-6

So there's your answer

8 0
3 years ago
Read 2 more answers
Could someone answer and explain these please? Thank you!
Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

x=(10 \times t)+(1 \times u)

x=10t+u

The two digit number 'y' is obtained by reversing the digits of x.

So, y=(10 \times u)+(1 \times t)

y=10u+t

Now, the value of x-y is expressed as:

x-y=(10t+u)-(10u+t)

x-y=10t+u-10u-t

x-y=9t-9u

x-y=9(t-u)

So, 9(t-u) is equivalent to (x-y).

Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = \frac{a}{1-r}

Since, the sum of the given infinite geometric series = 200

Therefore,\frac{a}{1-r}=200

Since, r=0.15 (given)

\frac{a}{1-0.15}=200

\frac{a}{0.85}=200

a=0.85 \times 200

a=170

The nth term of geometric series is given by ar^{n-1}.

So, second term of the series = ar^{2-1} = ar

Second term = 170 \times 0.15

= 25.5

So, the second term of the geometric series is 25.5






Step-by-step explanation:


8 0
3 years ago
GIVEN: LJ || WK || AP, PL || AG.
galina1969 [7]

Answer:

∠1 ≅ ∠2 ⇒ proved down

Step-by-step explanation:

#12

In the given figure

∵ LJ // WK

∵ LP is a transversal

∵ ∠1 and ∠KWP are corresponding angles

∵ The corresponding angles are equal in measures

∴ m∠1 = m∠KWP

∴ ∠1 ≅ ∠KWP ⇒ (1)

∵ WK // AP

∵ WP is a transversal

∵ ∠KWP and ∠WPA are interior alternate angles

∵ The interior alternate angles are equal in measures

∴ m∠KWP = m∠WPA

∴ ∠KWP ≅ ∠WPA ⇒ (2)

→ From (1) and (2)

∵ ∠1 and ∠WPA are congruent to ∠KWP

∴ ∠1 and ∠WPA are congruent

∴ ∠1 ≅ ∠WPA ⇒ (3)

∵ WP // AG

∵ AP is a transversal

∵ ∠WPA and ∠2 are interior alternate angles

∵ The interior alternate angles are equal in measures

∴ m∠WPA = m∠2

∴ ∠WPA ≅ ∠2 ⇒ (4)

→ From (3) and (4)

∵ ∠1 and ∠2 are congruent to ∠WPA

∴ ∠1 and ∠2 are congruent

∴ ∠1 ≅ ∠2 ⇒ proved

8 0
2 years ago
What is the value of the function when x = 0?<br><br> x −2 0 1 3 6<br> y 1 3 4 2 0
labwork [276]
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6 0
3 years ago
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