Answer:
A) See the picture
B) 14
C) 45%
Step-by-step explanation:
A) To create a histogram like the one on the picture you can use an online tool like socscistatistics where the number of classes is customizable
B) Because the question B and C have to be responded using a frequency table with 8 classes the answer is 14; the method of using cumulative frequency tables should only be considered as a way of estimation, that is because you obtain values that depend on your choice of class intervals. The way to get a better answer would be to use all the scores in the distribution
Pc1 = 100*(4/40) = 10
Pc2 = 100*(4/40) = 10
Pc3 = 100*(3/40) = 7.5
Pc4 = 100*(11/40) = 27.5
Pc5 = 100*(5/40) = 12.5
Pc6 = 100*(4/40) = 10
Pc7 = 100*(7/40) = 17.5
Pc8 = 100*(2/40) = 5
Pc8 + Pc7 + Pc6 + Pc5 + Pc4 + Pc3 + Pc2 = 90%
Therefore, From class 8 to class 2 is the top 90% of the applicants and the minimum score is 14.
C) Scores equal to or greater than 20 are from class 8 to class 5
Pc8 + Pc7 + Pc6 + Pc5 = 45%
Part A)
F(s) = 3s + 35 is the number of flowers
S(w) = 15w is the number of seeds planted
Since s = 15w, replace s in the first equation with 15w and simplify:
F(s) = 3(15w) + 35
F(s) = 45w + 35
B)
The composited equation calculates the number of flowers That bloomed.
C) replace w with 36 and solve.
45(w) + 35 = 45(36)+35 = 1620 + 35 = 1,655 flowers bloomed in 36 weeks.
Answer: 19 but yes
Step-by-step explanation:
15 divide 30 by 2 and you have your answer
42 can be
1 x 42, or
2 x 21, or
3 x 14, or
6 x 7 .