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pantera1 [17]
2 years ago
7

What is the solution set of fx x>-5) u {xx<5)?

Mathematics
1 answer:
Cloud [144]2 years ago
7 0
Huh.........

Explanation:

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4 more than twice a number
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Twice means two times something so2a. Four more than means adding for so your answer is 2a+4
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The original price of a coffee table is d dollars. You use a coupon and buy the table for (d − 4) dollars. You paint the table a
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Answer:

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2 years ago
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PLEASE HELP!!!!!!
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Is the last one 6.04
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2 years ago
USE A MODEL Olivia and her brother William had a bicycle race. Olivia rode at a speed
Anni [7]

Answer:

Let the total distance Aileen ran be 'x'

Let the distance ran by Andrew be 'y'

Refer to graph attached for graphical representation of distance travelled by both.

Applying the formula,

distance=speed*time

x=20*t      Equation  1

y= 15*t       equation 2

Since it can be easily understood by the graph attached, that

x=150+y  equation 3

Now putting values of x and y in equation 3

20*t =150 +15*t.

5t= 150

t=30 seconds.

putting the values of t in both the equation 1 and 2

x=20t

=20*30

x  = 600 feet

So the distance ran by Aileen is 600 feet, whereas Andrew ran 450 feet.

Step-by-step explanation:

Do not mind the names just change them. I had the same question before with different names so that is why. Hope this helps:)

7 0
2 years ago
Find the general solution of the given differential equation. cos^2(x)sin(x)dy/dx+(cos^3(x))y=1 g
eimsori [14]

If the given differential equation is

\cos^2(x) \sin(x) \dfrac{dy}{dx} + \cos^3(x) y = 1

then multiply both sides by \frac1{\cos^2(x)} :

\sin(x) \dfrac{dy}{dx} + \cos(x) y = \sec^2(x)

The left side is the derivative of a product,

\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)

Integrate both sides with respect to x, recalling that \frac{d}{dx}\tan(x) = \sec^2(x) :

\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx

\sin(x) y = \tan(x) + C

Solve for y :

\boxed{y = \sec(x) + C \csc(x)}which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}.

7 0
1 year ago
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