Twice means two times something so2a. Four more than means adding for so your answer is 2a+4
Answer:
Let the total distance Aileen ran be 'x'
Let the distance ran by Andrew be 'y'
Refer to graph attached for graphical representation of distance travelled by both.
Applying the formula,
distance=speed*time
x=20*t Equation 1
y= 15*t equation 2
Since it can be easily understood by the graph attached, that
x=150+y equation 3
Now putting values of x and y in equation 3
20*t =150 +15*t.
5t= 150
t=30 seconds.
putting the values of t in both the equation 1 and 2
x=20t
=20*30
x = 600 feet
So the distance ran by Aileen is 600 feet, whereas Andrew ran 450 feet.
Step-by-step explanation:
Do not mind the names just change them. I had the same question before with different names so that is why. Hope this helps:)
If the given differential equation is
then multiply both sides by 
:
The left side is the derivative of a product,
![\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%3D%20%5Csec%5E2%28x%29)
Integrate both sides with respect to 
, recalling that 
:
![\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%5C%2C%20dx%20%3D%20%5Cint%20%5Csec%5E2%28x%29%20%5C%2C%20dx)
Solve for 
:
![\boxed{y = \sec(x) + C \csc(x)}which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csec%28x%29%20%2B%20C%20%5Ccsc%28x%29%7D%3C%2Fp%3E%3Cp%3Ewhich%20follows%20from%20%5Btex%5D%5Ctan%28x%29%3D%5Cfrac%7B%5Csin%28x%29%7D%7B%5Ccos%28x%29%7D)
.
