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kakasveta [241]
3 years ago
14

The store bought a computer for $850, and sold it for $1105. What percentage was the markup?

Mathematics
1 answer:
Damm [24]3 years ago
7 0

Answer:

30%

Step-by-step explanation:

1105 - 850 = 255

255 ÷ 850 = 0.3

0.3×850=30

30%

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In 2009, the American Time Use Survey found that the average American spends 2.8 hours a day watching TV. Suppose the standard d
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4.72 hours/day

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Standard deviation (σ) = 1.5 hours a day

The 90th percentile (upper 10%) of a normal distribution has an equivalent z-score of roughly z = 1.282. The minimum time spent watching TV, X, at the 90th percentile is:

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On a typical day, you must watch at least 4.72 hours of TV to be in the upper 10%.

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We have to show that this is a square, meaning all the sides are perpendicular and the same distance.  

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