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yanalaym [24]
3 years ago
10

What is the axis of symmetry for the graph of this equation?

Mathematics
2 answers:
ASHA 777 [7]3 years ago
5 0
<h2>Hello!</h2>

The answer is: The axis of symmetry is: x=1

<h2>Why?</h2>

The axis of symmetry is a vertical line that divides the function (parabola)into two congruent halves, and it can be found using the following equation:

x=-\frac{b}{2a}

From the given function (parabola) we have that:

a=2\\b=-4\\c=2

So, finding the axis of symmetry we have:

x=-\frac{-4}{2*2}=\frac{4}{4}=1

So, the axis of symmetry is: x=1

Have a nice day!

den301095 [7]3 years ago
4 0

Answer:

x=1

Step-by-step explanation:

x=-b/(2a)

a=2

b=-4

c=2

-(-4)/(2*2)=4/4 or 1

x=1

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Answer:

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Step-by-step explanation:

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5 0
3 years ago
Question 9 (1 point)
Romashka [77]

Answer:

Step-by-step explanation:

League A                   League B

151.12                            163.25

148                                157

26.83                             24.93

29                                  136

136                                145

167                                178

207                               256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(82.5-1.5\times 76.56,159.06+1.5\times 76.56)

(-32.34,273.9)

So, There is no outlier

Maximum = 207

2)

League B in ascending order :

24.93,136,145,157,163.25,178,256

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(140.5-1.5\times 30.125,170.625+1.5\times 30.125)

(95.3125,215.8125)

24.93 and 256 are outliers  

Maximum = 256

5 0
3 years ago
Fill in the table and then round to the given place 225.286
Viefleur [7K]
The answer is 1.4.3. thats the answer rounded
7 0
3 years ago
Find the measure of each marked angle!!
tamaranim1 [39]

Answer:

60 is the answer

Step-by-step explanation:

10x - 20 = 7x + 4 (Corresponding angles)

10x - 7x = 20 + 4

3x = 24

x = 8

substituting the values,

10(8) - 20

80 - 20

60

similarly the other angle is 60 since they are corresponding angles.

8 0
3 years ago
Help please ?! I need answers really fast
Aleonysh [2.5K]
The value of x in terms of p is 15/p.

The value of x when p is -5 is -3.

Pls tell me if i’m wrong in any way!
6 0
3 years ago
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