Answer:
$4000
Step-by-step explanation:
so $2800 was the starting price
100%-30%=70%
So 2800=70%
2800/7=400
400=10%
400*10=$4000
I ALREADY ANSWER THIS xdddddddddddddddddddddddddddddddddd
Answer:
54 mph
Step-by-step explanation:
Let s represent the slower speed. The product of speed and time is distance, which did not change between the two trips. So, we have ...
1.8(s +6) = 2(s)
10.8 = 0.2s . . . . eliminate parentheses, subtract 1.8s
54 = s . . . . . . . . divide by 0.2
Fran's average speed on Sunday was 54 miles per hour.
____
Her trip was 108 miles long.
Answer:
The number that goes in place of the question mark is 2.
Step-by-step explanation:
Let's solve it!
3x² + 12x - 24 = 0
First we can factor 3 out of each term:
x² + 4x - 8 = 0
Now we'll add 12 to both sides to complete the square:
x² + 4x + 4 = 12
And finish it off:
(x + 2)² = 12
So the answer to the question is 2
Bonus:
We can also now solve this for x:
(x + 2)² = 12
x = √12 - 2
x = 2√3 - 2
x ≈ 2 × ±1.732 - 2
x ≈ 1.464, -5.464
5).
and
6).
The volume of a sphere is
(4/3) (pi) (radius)³ .
In #5, the 'pi' is already there next to the answer window.
You just have to come up with the (4/3)(radius³).
Remember that the radius = 1/2 of the diameter.
7). The volume of a cylinder is
(pi) (radius²) (height) .
Divide the juice in the container by the volume of one can,
to get the number of cans he can fill.
8). The volume of a cone is
(1/3) (pi) (radius of the round bottom)² (height) .
He starts with a small cone, he then adds clay to it to make it higher.
The question is: How much clay does he ADD to the short one,
to make the bigger one ?
Use the formula to find the volume of the short one.
Use the formula again to find the volume of the bigger one.
Then SUBTRACT the smaller volume from the bigger volume.
THAT's how much clay he has to ADD.
Notice that the new built-up cone has the same radius
but more height than the first cone.
_______________________________________
Don't worry if you don't understand this.
The answer will be this number:
(1/3) (pi) (radius²) (height of the big one minus height of the small one).