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GaryK [48]
3 years ago
14

Q(x)=4-x over (x-4)(x+2)

Mathematics
1 answer:
lapo4ka [179]3 years ago
7 0
Q(×)=4-x / x^2-2x-8
What are u trying to do???
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Simon walks a total of 45.55 miles in march sand 35.7 miles in April.
ollegr [7]

Answer:

81.25

45.55 + 35.7

3 0
3 years ago
Given the linear equation 3x + y = 5, find the slope of its graph
umka2103 [35]

Answer:

B) -3

Step-by-step explanation:

1. First you have to write the equation in slope intercept form. To do that, you must have y be alone on one side.

2. move the 3x to the right side with the 5 by subtracting 3x from both sides. Since 3x will cancel on the left, y will be left alone. y=-3x+5

3. Now that you're in slope intercept form, you can find the slope easily. The slope will always be the number in front of x. In this case, the number in front of x is -3. Therefore, -3 is your slope!

7 0
3 years ago
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The price of a 7​-minute phone call is ​$1.05. What is the price of an 11​-minute phone​ call?
lubasha [3.4K]

Answer:

Should be 1.64

Step-by-step explanation:

4 0
3 years ago
HELP IM SOO CONFUSED!
Maksim231197 [3]

Answer:

16=2b+4

12=2b

b=6

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4 0
3 years ago
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Consider f and c below. f(x, y) = (7 + 8xy2)i + 8x2yj, c is the arc of the hyperbola y = 1/x from (1, 1) to 3, 1 3 (a) find a fu
KonstantinChe [14]

\dfrac{\partial f}{\partial x}=7+8xy^2

\dfrac{\partial f}{\partial y}=8x^2y

The first equation gives

f(x,y)=7x+4x^2y^2+g(y)

Differentiating with respect to y gives

8x^2=8x^2y+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=K

for some constant K. So

f(x,y)=7x+4x^2y^2+K

and by the fundamental theorem of calculus,

\displaystyle\int_C\nabla f\cdot\mathrm d\vec r=f\left(3,\frac13\right)-f(1,1)=25-11=\boxed{14}

4 0
3 years ago
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