Answer: There are 4 people who only go to the game on Saturday.
Step-by-step explanation:
Let the number of people go on Saturday be n(A).
Let the number of people go on Sunday be n(B).
Since we have given that
n(A) = 8
n(B) = 12
n(A∪B) = 16
According to rules, we get that

So, n(only go on Saturday) = n(only A) = n(A) - n(A∩B) = 8-4 = 4
Hence, there are 4 people who only go to the game on Saturday.
Answer:
-6re−r [sin(6θ) - cos(6θ)]
Step-by-step explanation:
the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ
x = e−r sin(6θ), y = er cos(6θ)
δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)
δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)
∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ
= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]
= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))
= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]
= -6re−r [sin(6θ) - cos(6θ)] since [cos²(6θ) + sin²(6θ)] = 1
Answer:
It would take 5.9 years to the nearest tenth of a year
Step-by-step explanation:
The formula of the compound continuously interest is A = P
, where
- A is the value of the account in t years
- P is the principal initially invested
- e is the base of a natural logarithm
- r is the rate of interest in decimal
∵ Serenity invested $2,400 in an account
∴ P = 2400
∵ The account paying an interest rate of 3.4%, compounded continuously
∴ r = 3.4% ⇒ divide it by 100 to change it to decimal
∴ r = 3.4 ÷ 100 = 0.034
∵ The value of the account reached to $2,930
∴ A = 2930
→ Substitute these values in the formula above to find t
∵ 2930 = 2400
→ Divide both sides by 2400
∴
= 
→ Insert ㏑ in both sides
∴ ㏑(
) = ㏑(
)
→ Remember ㏑(
) = n
∴ ㏑(
) = 0.034t
→ Divide both sides by 0.034 to find t
∴ 5.868637814 = t
→ Round it to the nearest tenth of a year
∴ t = 5.9 years
∴ It would take 5.9 years to the nearest tenth of a year
Answer:
4(4 + 9)
Step-by-step explanation:
Well... you can divide each by 4 and you get 4(4 + 9)
That's about all you can do for the distributive property.