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3 years ago

5

the original price of a coat was $290.00, the store put the coat on sale for $175.70 how much did the store reduce the price of

the coat

2 answers:

Ghella [55]3 years ago

7 0

2.90 - 175.70 = 114.3

UkoKoshka [18]3 years ago

3 0

Inital-sale
$290.00
-$175.70
--------------
=$114.3

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Aleks [24]

Answer:

Probability of picking an even and then even number = $\frac{1}{6}$

Step-by-step explanation:

Probability of picking a card with even number,

P(even 1) = $\frac{\text{favorable outcomes}}{\text{Total outcomes}}$ = $\frac{\text{even cards}}{\text{Total number of cards}}$

= $\frac{2}{4}$

= $\frac{1}{2}$

Followed by picking a card which is even without putting the first card back.

So an even card is to be picked out of remaining 3 cards.

P(even 2) = $\frac{\text{favorable outcomes}}{\text{Total outcomes}}$

= $\frac{1}{3}$

Now probability of both events = P(even 1) × P(even 2)

= $\frac{1}{2}\times \frac{1}{3}$

= $\frac{1}{6}$

Therefore, probability of both the events will be $\frac{1}{6}$ .

5 0

3 years ago

721 lbs per week to kg per second please show work

Oduvanchick [21]

Answer: Hi! So, 1 lbs per week are equal to 7.4999e-7 kilograms per second. We can use this to convert lbs per week to kg per second. 721 x 7.4999e-7 = 0.000540741!

8 0

2 years ago

In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p

hichkok12 [17]

Answer:

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

4 0

3 years ago

12 ten thousands, 8 thousands,14 hundreds, 7 ones in standard form

coldgirl [10]

12 x 10000 = 120000
8 x 1000 = 8000
14 x 100 = 1400
7 x 1 = 7

120000 + 8000 + 1400 + 7
129407 is your answer

hope this helps

8 0

3 years ago

I don't get this part can somebody help pls?

meriva

Answer:

the ground level is -2

Step-by-step explanation:

hope this helps

7 0

3 years ago