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3 years ago

Find the inverse of the function:f(x) = 3x + 6

Mathematics

1 answer:

natta225 [31]3 years ago

4 0

Answer:

x = -2

Step-by-step explanation:

Pull out like factors :

-3x - 6 = -3 • (x + 2)

Solve : -3 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solve : x+2 = 0

Subtract 2 from both sides of the equation :

x = -2

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What is the simplified form of −x2 (2x3 + 5x2 + 6x)?

allsm [11]

I Believe It’s 2x^5-5x^4-6x^3

6 0

3 years ago

Determine how many, what type, and find the roots for f(x) = x3 - 4x2 – 16x + 64. SHOW WORK!

Mice21 [21]

Answer:

x=4

Step-by-step explanation:

x^3-4x^2-16x+64

(x^2-16)(x-4)

x-4=0

+4 +4

x=4

x^2-16=0

+16 +16

x^2=16

√ x^2=√ 16

x=4

7 0

3 years ago

Why does.the equation y=3x+5 NOT represent a proportional relationship

sergiy2304 [10]

Answer:

The equation not represent a proportional relationship because the line don't passes through the origin

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem we have

$y=3x+5$

This is the equation of the line in slope intercept form

where

the slope is m=5

the y-intercept is b=5

Remember that in a proportional relationship the value of b must be equal to zero (because the line passes through the origin)

therefore

The equation not represent a proportional relationship because the line don't passes through the origin

5 0

3 years ago

Rationalize the denominator x-3/√x+2 - √5

Pachacha [2.7K]

I got this answer, I think it’s correct though.

8 0

2 years ago

What types of numbers are undefined when they are under a radical sign? If you were dealing with the number √-1, would it be def

sveta [45]

1) the types of number are the negative integers (e.g √-1 √-3 √-5 are not defined)
2) the answer is No, proof: 2x√-1 is not defined because √-1 doesn't exist
3) the answer is No, proof: √-1 - 3 is not defined because √-1 doesn't exist
4) the answer is Yes, proof: (√-1 )²= -1 this is a real number
5) the answer is No, proof: (√-1 )^3= (√-1 )²(√-1 )= - 1(√-1 ), and - 1(√-1 ) is not defined because √-1 doesn't exist
6) the result would be defined with the following cases:
√-1+n, n>1
√-1xn, n<0
√-1/n, n<0
7) the result would not be defined with the following cases:
√-1+n, n<0
√-1xn, n>0
√-1/n, n>0
8) to square 3 + √-1, I use the method of complex number
i²= -1, it implies i= √-1
so 3+√-1=3+i, and then (3+√-1)²=(3+i)²= 9 -1+6i= 8-i= 8-√-1
9) it is used for finding complex roots of a number

3 0

3 years ago

Find the inverse of the function:f(x) = 3x + 6​

Find the inverse of the function:f(x) = 3x + 6