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4 years ago

Common factors ???? the last one is 30, 84 , 126

Mathematics

1 answer:

svp [43]4 years ago

5 0

All these numbers eventually have a common factor, A number that can be reached by multiplying different numbers, like 6 x 4 = 24 and 8 x 3 = 24.
You can list them, or find them different ways. For example 48 x 10 = 480 and 20 x 24 = 480. 48 and 20 share this ability to reach 480 through multiplication

You might be interested in

Write the slope-intercept form of the equation of the line satisfying the given conditions through(3,-3); slope=-4

il63 [147K]

Answer:

y=-4x+9

Step-by-step explanation:

y-y1=m(x-x1)

y-(-3)=-4(x-3)

y+3=-4(x-3)

y=-4x+12-3

y=-4x+9

7 0

4 years ago

Can someone please help me with b, d, and 9-13? I already drew a number line, thanks in advance! :)

inessss [21]

B)
$\frac{3}{13} = s$
d)
$\frac{5}{4} = s$
9) I'm not really sure how to answer it, but I guess like 2.1, 2.2, 2.5, etc.,

10)
${2}^{2} = 4$
${3}^{2} = 9$
so {5, 6, 7, 8} is the answer

11) for some reason it won't let me insert a picture but put place
$\sqrt{4}$
above 2, and then place
$\sqrt{9}$
above 3, and then place
$\sqrt{7}$
in between 2 and 3, but place it a little closer to three since
$\sqrt{7} = 2.65$
12) place
$\sqrt{5}$
between 2 and three, but closer to two since
$\sqrt{5} = 2.24$
and also
$\sqrt{5} < \sqrt{7}$
and for number 13) the square root of 144 is 12, and the square root of 169 is 13, so any numbers between 12 and 13 will work.

I hope this helped and if not, message me and ill try to explain!

8 0

3 years ago

One mirror is to be in the shape of a triangle whose height is 6 feet less than twice the base of the mirror. If the mirror has

Vlad1618 [11]

Answer:

Base of the mirror is 12 feet and height of the mirror is 18 feet.

Step-by-step explanation:

Given:

Area of the triangular mirror = 108 sq ft.

Let base (b) of the mirror be x.

Now given:

height is 6 feet less than twice the base of the mirror

So we can say that;

Height (h) = $2x-6$

We need to find the base and height of the mirror.

Solution:

Now we know that mirror is in triangular shape so we will apply area of triangle formula to find base and height.

Now Area of triangle is half times base times height.

framing in equation form we get;

$108=\frac{1}{2} \times x \times(2x-6)\\\\108=\frac{1}{2}\times x \times 2(x-3)\\\\108=x(x-3)\\\\108=x^2-3x\\\\x^2-3x-108=0$

Now we will find the roots of x by factorizing the equation we get;

$x^2-12x+9x-108=0\\\\x(x-12)+9(x-12)=0\\\\(x-12)(x+9)=0$

Now we will solve for 2 values of x we get;

$x-12=0\\\\x=12\ ft\\\\Also;\\\\x+9=0\\\\x=-9\ ft$

Now we get 2 values of 'x' one positive and one negative.

Since x is base of the triangle which cannot be negative.

so we will discard the negative value.

Hence;

base of triangle = 12 ft

Height of the triangle = $2x-6=2\times12-6 =24-6 =18\ ft$

Hence Base of the mirror is 12 feet and height of the mirror is 18 feet.

7 0

4 years ago

Can anyone explain to me how to do this question ? ty !!

julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0

3 years ago

In Triangle WVU, what sides include Angle V?

NeTakaya

Answer:

∴ $WV$ and $UV$ this two sides include $\angle V$

Step-by-step explanation:

Given;

A triangle $WVU$

We can see the figure of the triangle $WVU$

Where the $\angle V$ or $\angle WVU$ made by two sides $WV$ and $UV$ .

So $WV$ and $UV$ this two sides include $\angle V$

7 0

3 years ago