All categories

3 years ago

Find the distance between the points (-2,3) and (3,-9)

Mathematics

1 answer:

kakasveta [241]3 years ago

5 0

Answer:

13 units

Step-by-step explanation:

Put the numbers in the distance formula and do the arithmetic.

d = √((x2 -x1)² +(y2 -y1)²)

= √((3 -(-2))² +(-9-3)²) = √(5² +(-12)²) = √(25 +144)

d = √169 = 13

The distance between the points is 13 units.

You might be interested in

Geraldo wants to start a group bike ride on Sunday mornings for students at his school. He asked 30 students in the lunchroom ho

blsea [12.9K]

4 is the answer because there are only 4 numbers greater than 10.Those are the people who ride bikes ore than 10 times.

3 0

3 years ago

Read 2 more answers

The topic is about secant tangle angles

yuradex [85]

Answer:

Step-by-step explanation:

360-(104+104+111)=41

6 0

3 years ago

Read 2 more answers

Which of the following best describes the folding method needed to create a

vivado [14]

Fold tracing paper so that the line segment's endpoints line up with each other , Option D is the correct answer.

<h3>What is a Perpendicular ?</h3>

A perpendicular is a line drawn at 90 degree to a given line or line segment .

Fold tracing paper so that the line segment's endpoints line up with each other.

After drawing a line segment ,

when the end point will be on each other and a crease will be made by pressing the paper , The crease formed will be perpendicular to the line segment.

Therefore, Option D is the correct answer.

To know more about Perpendicular

brainly.com/question/18271653

#SPJ1

3 0

1 year ago

The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de

antoniya [11.8K]

Answer:

a) $P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b) $P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c) $P(A') = 1-P(A) =1-0.4=0.6$

d) $P(A \cup B) =0.4 +0.8-0.2 =1.0$

e) The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

Step-by-step explanation:

We have the following space provided:

$S= [a,b,c,d,e]$

With the following probabilities:

$P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2$

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

$P(A) = 0.1+0.1+0.2 = 0.4$

$P(B) =0.2+0.4+0.2=0.8$

Determine:

a. P(A)

$P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b. P(B)

$P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c. P(A’)

From definition of complement we have this:

$P(A') = 1-P(A) =1-0.4=0.6$

d. P(AUB)

Using the total law of probability we got:

$P(A \cup B) =P(A) +P(B)-P(A \cap B)$

For this case $P(A \cap B) = P(c) =0.2$ , so if we replace we got:

$P(A \cup B) =0.4 +0.8-0.2 =1.0$

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

8 0

3 years ago

Please help me and I’ll give you brainiest!!!!!!!!!

dsp73

Answer:

S L O P E

Explain:

S L O P E

4 0

2 years ago

Read 2 more answers