Question

If a chain of 30 identical short springs linked end-to-end has a stiffness of 450 N/m, what is the stiffness of one short spring?

Answer 1

The stiffness of one short spring is 13500 N/m

Solution:

We are given a chain with number of spring N = 30 and linked end to end ( in series) and stiffness of this chain is 450 N/m

We have to find the stiffness of one short spring

The springs are identical, which means they have same stiffness

The stiffness of one spring in series is given as:

$k_i = N \times k_s$

Where,

N is the number of springs

$k_i$ is the stiffness of one spring

$k_s$ is the stiffness of this chain

Substituting,

$N = 30\\\\K_s = 450$

Therefore,

$k_i = 30 \times 450\\\\k_i = 13500$

Thus the stiffness of one short spring is 13500 N/m