What is the area of the two-dimensional cross section that is parallel to face ABC ?
2 answers:
Answer:
The area of the two-dimensional cross section that is parallel to face ABC. that is Area of Δ DEF = 84 ft²
Step-by-step explanation:
Given : A triangular prism with some side measurement.
We have to find the area of the two-dimensional cross section that is parallel to face ABC.
Since, the cross section that is parallel to face ABC.
Since, face parallel to ABC is DEF .
And DEF is a triangle with ∠ E = 90°
So, Area of right angled triangle
Base = 24 ft
and height is 7 ft
So, Area of Δ DEF =
Simplify , we have,
Area of Δ DEF = 84 ft²
Thus, The area of the two-dimensional cross section that is parallel to face ABC. that is Area of Δ DEF = 84 ft²
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Answer:
A) Area =
B) Domain = {x < 24}
Step-by-step explanation:
<u>Complete Question:</u>
A car dealership has 24ft of dividers with which to enclose a rectangular play space in a corner of a customer lounge. The sides against the wall require no partition. Suppose the play space is x feet long.
A) express the area of the play space as a function of x
B) find the domain of the function
Solution:
A)
The rectangle has area of length * width
length is x
so width will be 24 - x
Hence, the area will be:
Area = x(24 - x)
Area =
B)
Domain is the set of x values that make the function defined.
The domain will be all values less than 24.
Because if you take 24, the area would be 0 [doesn't make sense]
if you take anything over 24, the area would be negative [not possible]
Hence, the domain is:
Domain = {x < 24}