Answer:
d. does not exist
Step-by-step explanation:
The given limits are;
,
and 
We want to find

By the properties of limits, we have;

This gives us;

Division by zero is not possible. Therefore the limit does not exist.
Associative property moves the parenthesis
Choice B
Sorry I am a little late...
a = -2
b = -9
Here is how to solve the problem.
First thing I did was multiply the first equation by -2 so that we can eliminate the the b. After you multiply it by -2, your new equation is -16a + 8b = -40.
You leave the second equation alone and all you do is combine like terms. So -16a+5a is -11. And you eliminate the b. Then you're going to do -40+62 which is 22. So it's -11a=22 and then you have to solve for a. What I did was I multiplied the whole thing by minus to turn the a positive. So then it's 11a=-22. Pretty easy, the final step is to simplify. -22/11 is -2. ;D
So there you have your first answer.
a = -2
Now we're going to use the first answer to help us find b.
For the second equation, all you're going to do is plug in that a.
5 (-2)-8b=62
-10 - 8b = 62
Now we move the -10 to the other side...
-8b = 62 + 10
-8b = 72
Multiply the whole thing by negative once again to turn the b positive.
Now we have 8b = -72
The final step is to simplify. -72/11 = -9
b = -9
Hope this makes sense! Also I had the same question on my test and I got it right. :)
The solution would be like
this for this specific problem:
86 + 80 = 166
166 / 2 = 83
<span>So the class average is 83.
</span><span>In colloquial language, an </span>average<span> is the sum of a list of numbers divided by the
number of numbers in the list.</span>
You began to do the equation from left to right. 8-10 = -2, so -2+5= 3, 3+6= 9f