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3 years ago

Can someone show me how to work out this example? (5+44+182−20−10)÷(2+5)

Mathematics

1 answer:

lora16 [44]3 years ago

6 0

Answer:

approximately 35.9

Step-by-step explanation:

(5+44+182-20-10)÷(2+5)

(99+182-20-10)÷(7)

(281-20-10)÷(7)

(261-10)÷÷(7)

(251)÷(7)

approximately 35.9

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mrs_skeptik [129]

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3 years ago

Help help help help math math

omeli [17]

<h3>Answer:</h3>

<h3>Solution:</h3>

First, n*7 can be written as 7n.
Then, 7*5 is equivalent to 35.
So we have
7n=35
In order to find the value of n, we need to divide both sides by 7:
n=5

Hope it helps.

Do comment if you have any query.

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2 years ago

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3 years ago

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Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C

Lesechka [4]

Answer:

Solution : $-\frac{3}{4}-\frac{3}{4}i$

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]$

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

$\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}$

= $-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)$ ÷ $2\sqrt{2}\left(0-1\right)i$

= $3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right)$ ÷ $-2\sqrt{2}i$

= $\frac{3\left(1-i\right)}{\sqrt{2}}$ ÷ $2\sqrt{2}i$ = $-3-3i$ ÷ $4$ = $-\frac{3}{4}-\frac{3}{4}i$

As you can see your solution is the last option.

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3 years ago

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