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Mars2501 [29]
3 years ago
5

I need Help please!!

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0
I think it’s A because the s is between P&Q and S&C if it’s wrong I’m sorry!
You might be interested in
How do I use substitution to solve a system of linear equations?
Pachacha [2.7K]

Answer:

the substitution method is one way to solve linear equation. the substitution method is when substitute the one y value with the other:

example :

x+y=10

y=10-x ( value of y)

2x+y=12 ( substitute the value of y in the equation )

2x+(10-x)=12

2x+10-x=12 ( now solve for x)

x=12-10

x=2 ( substitute the value of x in the equation x+y=10)

x+y=10

2+y=10

y=10-2

y=8

( i hope it helps)

8 0
3 years ago
Victoria is 4 years older than her neighbor. the sum of their ages is no more than 14 years.enter an inequality that can be used
elena55 [62]
V is 4 more tha x
v=4+x
sum is no more than 14
v+x≤14

sub 4+x for v
4+x+x≤14
4+2x≤14
minus 4 both sides
2x≤10
divide both sides by 2
x≤5
5+4=9

the neighboor's age is at most, 5 years
and victoria is 9 at most

7 0
3 years ago
Read 2 more answers
Round 1,658.013 too the nearest hundred
aalyn [17]

Answer: 1700.00

Step-by-step explanation: Maybe, maybe not.

5 0
3 years ago
If $x$ is the average of $13$, $-16$, and $6$ and if $y$ is the cube root of $8$, find $x^2 + y^3$. Please Help
Alekssandra [29.7K]

Answer:

If we have a set of N elements:

{x₁, x₂, ..., xₙ}

The mean value (also called the average value) Is calculated as:

Average = (x₁ + x₂ + ... + xₙ)/n

So if x is the average of 13, -16 and 6 ( a total of 3 values)

x will be equal to:

x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1

x = 1

And we know that:

y = ∛8

Remember that:

2*2 = 4

and

4*2 = 8

then

2*2*2 = 2^3 = 8

then ∛8 = 2.

So we have:

y = ∛8 = 2

Now we can replace these values in the equation:

x^2 + y^3

replacing:

x = 1

y = 2

we get:

1^2 + 2^3 = 1 + 8 = 9

5 0
3 years ago
in a circle a 60 sector has an area of 25 pi square feet. what is the circumference? leave your answer in terms of pi and in sim
belka [17]
The area of the sector is given by the equation,
                           A = πr²(x / 360°)
where x is the number of degrees in the figure. 
                           25π ft² = (πr²)(60/360)
The value of  r is 12.25 ft. Then, we use this value to calculate for the circumference of the sector. 
                           C = 2πr(x/360)
Substituting,
                              C = 2π(12.45)(60/360)
                                   C = 12.83 ft³
7 0
3 years ago
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