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Zielflug [23.3K]
3 years ago
10

Square root of 12 • by the square root of -1

Mathematics
1 answer:
Zinaida [17]3 years ago
7 0

Answer:

2i-/3

Step-by-step explanation:

This question involves imaginary numbers and simplifying radicals.

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Please help I need you​
mario62 [17]

Answer:

The answer is B.

Step-by-step explanation:

Diameter x Pi = Circumference

8 x 3.14 = 25.12

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4. What are the terms in the expression, 9- 4 + 3b + 7a?
Elan Coil [88]

Answer:

The terms are 9, 4, 3b and 7a.

The terms are 9 – 4 and 3b + 7a.

The terms are 9, -4, 3b, and 7a.

Step-by-step explanation:

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3 years ago
Sale Price: On opening day, a new music store offers a 16% discount on all electric guitars. If the regular price on a guitar is
svetoff [14.1K]
This can be done easily in a few ways. One, you could do equivelent fractions as this. 16 percent is the same as 16 over 100, or, 16/100, 100 being the total with an = sign with X over 550, or, X/550. you can multiply 16 by 500 and divide by 100 to get $88. Or you could do it my way, (prefered way). take the $550, divide it by 100, then multiply by 16 and get $88. either way you do this, you take away the $88 from $550 and get the sale price of [Drumroll please...]
<em><u>462 Dollars!</u></em>





6 0
3 years ago
Solve for x: 7x-3=3x+1
Elina [12.6K]

Answer:

x=1

Step-by-step explanation

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3 years ago
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James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
4 years ago
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