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telo118 [61]
3 years ago
8

What are the root of equation x2 -4x+29 in simplest a + b form

Mathematics
2 answers:
bagirrra123 [75]3 years ago
8 0

Answer:

Correct answer:  (x - 2 - 5 i) (x - 2 + 5 i)

Step-by-step explanation:

Given:

x² - 4 x + 29 = (  ) (  ) = ?  

this equation has no solution in the set of real numbers

x² - 4 x + 29 = x² - 2 · x · 2 + 2² - 2² + 29 = x² - 2 · x · 2 + 4 - 4 + 29

x² - 4 x + 29 = (x - 2)² + 25 = (x - 2)² - ( - 25) = (x - 2)² - ( - 1 · 5²)

We know that  the imaginary unit is the equal  i = √- 1 ⇒ i² = - 1

x² - 4 x + 29 = (x - 2)² - ( 5 i)²  this is the difference of the square

x² - 4 x + 29 = (x - 2 - 5 i) (x - 2 + 5 i)

these are conjugated complex numbers

God is with you!!!

Elanso [62]3 years ago
6 0
Idk hope this helps
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When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

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