Question

I'll give brainist because i can't do it

Answer 1

Answer:

Given

Step-by-step explanation:

Consider triangle ABD and triangle DCA,

AC=BD ( given that they are diameters)

Diameters of the same circle are equal

AD=AD (common side for both triangles)

<BAD= <CDA (angles in semicircles are 90°)

So since the right angle, hypotenuse and side are equal..

ABD is congruent to CDA

(Rhs congruence rule)

Hence proved..