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Anuta_ua [19.1K]
3 years ago
13

Need answers for questions in Boxes

Mathematics
1 answer:
ANTONII [103]3 years ago
4 0
A. Class A

A higher mean equals higher median overall.

B. Class B

The range of a data is the difference between the greatest value and the smallest value; a lower range would infer that the data's range is not very wide, and thus is not very varied.
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Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot
matrenka [14]

Answer:

\angle A \cong \angle D

Step-by-step explanation:

The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.

Thus, since John already knows that \overline{AB} \cong \overline{DE} and \overline{AC} \cong \overline{DF}, therefore, an additional information showing that the angle between \overline{AB} and \overline{DE} in ∆ABC is congruent to the angle between \overline{AC} and \overline{DF} in ∆DEF.

For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be \angle A \cong \angle D.

See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.

7 0
2 years ago
Classify the scenarios based on whether they are observational studies, experiments, or surveys. Scenario A: Twenty employees of
viktelen [127]

Answer:

Just took test, got it right. In the following:

Step-by-step explanation:

Scenarios:

A- Survey

B- Observation

C- Experiment

D- Survey

6 0
2 years ago
What is 0.25 ÷ 5.46 (show ur work)
kenny6666 [7]

Answer:

0.04578

Step-by-step explanation:

Hope this helps somewhat.

4 0
2 years ago
Read 2 more answers
A random sample of 20 purchases showed the amounts in the table (in $). The mean is $49.57 and the standard deviation is $20.28.
son4ous [18]

Answer:

The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.01 = 0.99, so z = 2.325

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.325*\frac{20.28}{\sqrt{20}} = 12.17

The lower end of the interval is the mean subtracted by M. So it is 49.57 - 12.17 = $37.40.

The upper end of the interval is the mean added to M. So it is 49.57 + 12.17 = $61.74.

The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

3 0
3 years ago
A phone company surveys a sample of current customers to determine if they use their phones most often to text or use the Intern
max2010maxim [7]

Answer:

a. 23

b. 13

c. 13/23

Step-by-step explanation:

a. 23 customers (13 +10) are on plan B (lol)

b. 13 customers on this plan text more often

c. Thus, 13/23 of customers on payment plan B use the phone most often to text

Hope this helps :)

3 0
3 years ago
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