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Artist 52 [7]
3 years ago
9

Multi step equation 7x+8=36​

Mathematics
2 answers:
Vitek1552 [10]3 years ago
4 0

Hey

Answer: 4

How do you find that out?

Divide the two numbers on the right, 36 and 8.

36/8=4

7 * 4 + 8 = 36

Hope this helped

gogolik [260]3 years ago
4 0

Answer:

Step-by-step explanation:

7 · x + 8 = 36

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The number of fish in a lake is decreasing by 400 every year, as described by the function below.
FrozenT [24]

Answer:

D: 7800

Can you give me brainliest :>

Step-by-step explanation:

3 0
2 years ago
Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t
Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1.f(x)=\frac{x^2+x-20}{x^2+4}

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345

3.h(x)=\frac{3x-5}{x^2-5x+7}

x^2-5x+7=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43

2.g(x)=\frac{x-17}{x^2+75}

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12

4.i(x)=\frac{x^2-9}{x-9}

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is  not continuous on the set of real numbers.

5.j(x)=\frac{4x^2-7x-65}{x^2+10}

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0

6.k(x)=\frac{x+1}{x^2+x+29}

x^2+x+29=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102

7.l(x)=\frac{5x-1}{x^2-9x+8}

x^2-9x+8=0

x^2-8x-x+8=0

x(x-8)-1(x-8)=0

(x-8)(x-1)=0

x=8,1

The function is not defined for x=8 and x=1

Hence, function l is not  defined for all real values.

8.m(x)=\frac{x^2+5x-24}{x^2+11}

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0
3 years ago
Help please help please
eduard

Answer:

 option \ C  3\frac{1}{3}

Step-by-step explanation:

\frac{|2a| - b}{3} \ , \ given \ a = \ 7 \ , \  b \  =\  4\\\\\frac{|2 \times 7| - 4}{3} = \frac{14 - 4}{3} = \frac{10}{3} = 3\frac{1}{3}

8 0
3 years ago
Read 2 more answers
A card was selected at random from a standard deck of cards. The suit of the card was recorded, and then the card was put back i
aleksklad [387]

Answer:

30%

Step-by-step explanation:

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3 years ago
Identify the conic that is formed by the intersection of the plane described and the double-napped cone.
DerKrebs [107]
<h3>Answer: B) hyperbola</h3>

If the cutting plane was parallel to the circular base of the cones, then we would have a circular cross section (assuming the plane doesnt cut through the vertex). However, we're told than the plane intersects both nappes, or cones, so it's not possible for the plane to be parallel to the base faces. We can rule out choice A.

We can rule out choice C and choice D for similar reasons. An ellipse only forms if the plane only cuts through one cone only, which is the same story for a parabola as well.

8 0
3 years ago
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