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tensa zangetsu [6.8K]
3 years ago
8

Help me please tysm!

Mathematics
2 answers:
crimeas [40]3 years ago
5 0

Answer:

  • 2 is the awnser

55.^

Becuase 6-5=1

1-6=5

5-4=1

1-3=2

Dominik [7]3 years ago
4 0
The answer is 2

the previous person is correct
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Which graph shows a positive relationship between variables ?
Brums [2.3K]

Answer:

scatter-plots

Step-by-step explanation:

Scatter plots are similar to line graphs in that they use horizontal and vertical axes to plot data points. However, they have a very specific purpose. Scatter plots show how much one variable is affected by another. The relationship between two variables is called their correlation .

5 0
4 years ago
Help thank you to who ever does I will mark brainliest.
Damm [24]

Answer:

V = 200.96 units ^3

Step-by-step explanation:

The volume of a cone is given by

V = 1/3 pi r^2 h

The radius is  4 and the height is 12

V = 1/3 ( 3.14 ) ( 4)^2 * 12

V = 200.96 units ^3

5 0
3 years ago
Read 2 more answers
Sprint to the finish the professional cyclist travels 380 meters in 20 seconds. At that rate how far does the cyclist travel in
kumpel [21]

Answer:

57 meters

Step-by-step explanation:

we know that

Sprint to the finish the professional cyclist travels 380 meters in 20 seconds

so

using proportion

Find out how far does the cyclist travel in 3 seconds

Let

x -----> the distance in meters

\frac{380}{20}\frac{m}{sec}=\frac{x}{3}\frac{m}{sec}\\\\x=380(3)/20\\\\x=57\ m

3 0
3 years ago
Read 2 more answers
An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0
3 years ago
Find the area of the composite figure!
Yuki888 [10]

Answer:

B

Step-by-step explanation:

8 times 8 = 64

17 times 8 = 136

64 + 136 = 200

4 0
3 years ago
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