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tensa zangetsu [6.8K]
2 years ago
8

Help me please tysm!

Mathematics
2 answers:
crimeas [40]2 years ago
5 0

Answer:

  • 2 is the awnser

55.^

Becuase 6-5=1

1-6=5

5-4=1

1-3=2

Dominik [7]2 years ago
4 0
The answer is 2

the previous person is correct
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Find the value of x in each figure number 5 please
Stells [14]
So the angle that's next to the 62 is 118. Now that means the other angles have to add up to 62. 62-14= 48 and 48/2 is 24 so X=24. Good luck! :)
7 0
3 years ago
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I have a rectangle house. it is ten feet wide and 20 feet long ​
coldgirl [10]

Answer:

200 in all

Step-by-step explanation:

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3 years ago
The scale of a map is 1:4 000 000. Hint: 1:4 000 000 means that 1cm on the map = 4 000 000 on the ground. The distance between L
GrogVix [38]

Answer:

325 km

Step-by-step explanation:

Given the scale :

1 : 4 ,000, 000

1cm measure in map = 4000000 on the ground

From the map :

Distance between Leeds and London = 8.125 cm

The actual distance on ground can be calculated thus :

1cm = 4,000,000

8.125cm = x

Cross multiply

x = 32500000 cm

Converting to kilometers :

1 km = 100,000 cm

x = 32500000

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100,000x = 32500000

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Hence, actual distance between Leeds and London is 325 km

3 0
3 years ago
Simplify 27^2.<br><br> please (thxx)
adoni [48]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =
const2013 [10]

Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}

The expression can be simplified as:

t = 2\sqrt{\frac{h}{16}}

For a player that has a hang time of 0.9s, the jump is found as follows:

0.9 = 2\sqrt{\frac{h}{16}}

\sqrt{\frac{h}{16}} = \frac{0.9}{2}

(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2

h = 16\left(\frac{0.9}{2}\right)^2

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

0.8 = 2\sqrt{\frac{h}{16}}

\sqrt{\frac{h}{16}} = \frac{0.8}{2}

(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2

h = 16\left(\frac{0.8}{2}\right)^2

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

More can be learned about equations at brainly.com/question/25537936

#SPJ1

3 0
2 years ago
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