Hi there!
Let's solve this problem step by step!

To find f(3) we must substitute x = 3 into the formula.

Now we use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.
Work out the exponents inside the parenthesis first.

And finally multiply.

Hence, the answer is D. 64.
~ Hope this helps you!
I think it’s the last one
Answer:
A.) Blocking occurs in an experiment when a certain experimental unit is divided or split into groups based on a certain criteria. In the experiment above, the experiment was blocked for class of runner, either professional or recreational. This is essential in other to limit the possible variability in our experiment. It is very possible thatvtve response of each class of runner may differ, therefore, it good practice to block for class of runner in other to contain the variation.
B.) Randomizing the type of shoe being worn by the runner ensures that we have given each runner an equal chance of selecting any type of shoe available,thereby eliminating biases which might emanate from fixing shoe type for each runner.
C.) Replication could simply be defined as the application of a certain treatment on more than one experimental unit. In the experiment above, by blocking for class of runner, hence having the professional and recreational units, and treatment applied to each experimental unit, Hence giving the experimenter the chance of controlling variation in the experiment.
Step-by-step explanation:
First you need to convert grams into kilograms. You know that 1kg=1000g
if 1kg=................. 1000g
x kg=.................5000g
x=5000/1000 = 5kg
Now you need to find the difference between an average-sized pumpkin and the <span>world's largest pumpkin which is:
784-5=779
So the right answer is 779.</span>
The minimum cost is achieved when 150 trees are produced giving a minimum cost of $27.5
Polynomial is an expression that involves the <em>operations of addition, subtraction, multiplication of variables.</em>
Let C represent the cost for buying and caring for n trees. Given that:
C = 0.001n² - 0.3n + 50.
The minimum cost is at dC/dn = 0, hence:
dC/dn = 0.002n - 0.3
0.002n - 0.3 = 0
0.002n = 0.3
n = 150
C(150) = 0.001(150)² - 0.3(150) + 50 = 27.5
The minimum cost is achieved when 150 trees are produced giving a minimum cost of $27.5
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