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Fantom [35]
3 years ago
14

Solve the equation for the variable. Make sure your answer is in simplest form.

Mathematics
2 answers:
tankabanditka [31]3 years ago
6 0

Answer:

x = \frac{2}{5}

Step-by-step explanation:

Given

- 3 - 39x = 11x - 23 ( subtract 11x from both sides )

- 3 - 50x = - 23 ( add 3 to both sides )

- 50x = - 20 ( divide both sides by - 50 )

x = \frac{-20}{-50} = \frac{2}{5}

maks197457 [2]3 years ago
3 0

Answer:

Here's your answer

hope this helped you

please mark as the brainliest (ㆁωㆁ)

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The following 5 questions are based on this information: An economist claims that average weekly food expenditure of households
liq [111]

Answer:

Null hypothesis:\mu_{1}-\mu_{0}\leq 0

Alternative hypothesis:\mu_{1}-\mu_{2}>0

SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705

b) 2.70

t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850

b. 1.85

p_v =P(Z>1.85)=0.032

b. 0.03

a. We can reject H(0) in favor of H(a)

Step-by-step explanation:

Data given and notation

\bar X_{1}=164 represent the mean for the sample 1

\bar X_{2}=159 represent the mean for the sample 2

\sigma_{1}=12.5 represent the population standard deviation for the sample 1

s_{2}=9.25 represent the population standard deviation for the sample B2

n_{1}=35 sample size selected 1

n_{2}=30 sample size selected 2

\alpha=0.05 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the expenditure of households in City 1 is more than that of households in City 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{0}\leq 0

Alternative hypothesis:\mu_{1}-\mu_{2}>0

We know the population deviations, so for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{(\bar X_{1}-\bar X_{2})-0}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Standard error

The standard error on this case is given by:

SE=\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}

Replacing the values that we have we got:

SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705

b. 2.70

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850  

P-value

Since is a one side right tailed test the p value would be:

p_v =P(Z>1.85)=0.032

b. 0.03

Conclusion

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

a. We can reject H(0) in favor of H(a)

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Answer:

The solution is obtained by dividing the number of flowers by the number of vases.

Step-by-step explanation:

The story problem is very straightforward. Normally, you need to read the problem and understand it.

Let's look at the question again.

Although we do not have all the quantities, we can still show how to solve the problem.

Let x be the total  number of flowers.

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Therefore, the number of flowers in each vase will be:

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Answer:

0.02 or 2% = Beta

Step-by-step explanation:

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Risk-free rate = 7 percent

Expected return on the market = 10 percent

Expected return on Security J = 13 percent

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Expected return on Security J = Risk-free rate + Beta (Expected return on the market - Risk-free rate)

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