All categories

2 years ago

Solve the equation for the variable. Make sure your answer is in simplest form.

Mathematics

2 answers:

tankabanditka [31]2 years ago

6 0

Answer:

x = $\frac{2}{5}$

Step-by-step explanation:

Given

- 3 - 39x = 11x - 23 ( subtract 11x from both sides )

- 3 - 50x = - 23 ( add 3 to both sides )

- 50x = - 20 ( divide both sides by - 50 )

x = $\frac{-20}{-50}$ = $\frac{2}{5}$

maks197457 [2]2 years ago

3 0

Answer:

Here's your answer

hope this helped you

please mark as the brainliest (ㆁωㆁ)

You might be interested in

If the probability of a student taking a calculus class is 0.10, the probability of taking a statistics class is 0.90, and the p

Stells [14]

Answer:

93% probability of a student taking a calculus class or a statistics class

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student takes a calculus class.

B is the probability that a student takes a statistics class.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student takes calculus but not statistics and $A \cap B$ is the probability that a student takes both these classes.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability of taking a calculus class and a statistics class is 0.07

This means that $A \cap B = 0.07$

The probability of taking a statistics class is 0.90

This means that $B = 0.9$ . So

$B = b + (A \cap B)$

$0.9 = b + 0.07$

$b = 0.83$

The probability of a student taking a calculus class is 0.10

This means that $A = 0.1$

$A = a + (A \cap B)$

$0.1 = a + 0.07$

$a = 0.03$

What is the probability of a student taking a calculus class or a statistics class

$A \cup B = a + b + A \cap B = 0.03 + 0.83 + 0.07 = 0.93$

93% probability of a student taking a calculus class or a statistics class

5 0

3 years ago

Can anyone help me?

ArbitrLikvidat [17]

Answer:

The factored form of 4m³ – 28m² – 120m is 4m(m – 10)(m + 3). The zeroes of the function would be m = 0, m = –3, and m = 10.

Step-by-step explanation:

I'll give this a shot.

4m³ – 28m² – 120m = 0 — The original expression

4m³ – 28m² – 120m — Did that 0 have any purpose? I just deleted it.

4(m³ – 7m² – 30m) — There's a common factor in here, 4. Let's pull that aside.

4m(m² – 7m – 30) — Actually, there's two common factors. The second one is m! Let's pull that out too!

To factor an expression, you have to break apart the middle term, so to speak. That's only possible if you can find two numbers whose product equals that of the outside terms and whose sum equals the middle term. Here, I'm just dealing with numbers and putting that variable aside.

–30 = 10 × –3

–30 = –10 × 3

–30 = –2 × 15

–30 = 2 × –15 — To solve for any potential factors, let's find all the numbers integers that multiply to –30

Now let's see which one adds up to –7!

15 – 2 = 13 — it's not this one

2 – 15 = –13 — nor this one

10 – 3 = 7 — we're pretty close! Let's switch that negative

3 – 10 = –7 — here we go! Here's our numbers!

4m[(m² – 10m) + (3m – 30)] — now we break apart the middle term. This is all multiplied by 4m, so that still encases everything with brackets.

4m[m(m – 10) + 3(m – 10)] — Factoring the two expressions

4m(m + 3)(m – 10) — simplifying to find our answer! Ta-da!

8 0

2 years ago

How much cash did Vera receive?

Ber [7]

There is a box labeled * Less Cash Received in the deposit ticket. The number in this box would be the amount of cash Vera received.

The number in this box is 80.00.

Vera received $80.00

4 0

3 years ago

Read 2 more answers

Dragon drop each expression two correctly classify it as having a positive or negative product

ioda

Step-by-step explanation:

We multiply it to find the product

positive times positive = positive

positive times negative = negative

negative times positive = negative

negative times negative = positive

$(-\frac{1}{3})(-\frac{1}{3})= \frac{1}{9}$

Negative and negative is positive , so product is positive

$(-\frac{1}{3})(\frac{1}{3})= -\frac{1}{9}$

Negative and positive is negative , so product is negative

$(\frac{1}{3})(-\frac{1}{3})= -\frac{1}{9}$

positive and negative is negative , so product is negative

$(\frac{1}{3})(\frac{1}{3})= \frac{1}{9}$

positive and positive is positive , so product is positive

7 0

3 years ago

. A survey showed that 1/3 of the students in the class liked blue. I/4 of the remainder liked red. The remaining 24 students li

Olin [163]

Answer:

Step-by-step explanation:

sdfsfsfdsdfsdfsdfsfsdfsdfsd

5 0

2 years ago