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mart [117]
3 years ago
14

The 150 residents of the town of wonderland were asked their age and whether they preferred vanilla, chocolate, or swirled froze

n yogurt. the results are displayed next. chocolate vanilla swirl under 25 years old 40 20 15 at least 25 years old 15 40 20 what is the probability that a randomly selected customer prefers vanilla?
Mathematics
1 answer:
asambeis [7]3 years ago
8 0
<span>Residents who are under 25 years and those above are mutually exclusive. Let V = number of persons who take Vanilla under 25yrs and V' be the number of residents who are at least 25yrs who take Vanilla. Okay, so P(V) = 40/150 and P(V') = 15/150 P(V or V') = 40/150 + 15/150 = 0.366</span>
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What is 30% of 60?<br><br> 180<br><br> 0.18<br><br> 1800<br><br> 18
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[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =
kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = 1-\frac{_{n}^{12}\textrm{P}}{12^2}

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= \frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})

= 0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0
3 years ago
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vredina [299]

Answer:

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Step-by-step explanation:

we can add together the sides of ΔABC and set it equal to the sum of the sides of ΔPQR

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combine 'like terms':

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subtract 6x from each side to get:

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subtract 3 from each side to get:

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CHECK:

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